Answer:
Required Probability = 0.97062
Step-by-step explanation:
We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.
Let X = weight of the newborn baby, so X ~ N(
)
The standard normal z distribution is given by;
Z =
~ N(0,1)
Now, probability that the weight will be less than 5026 grams = P(X < 5026)
P(X < 5026) = P(
<
) = P(Z < 1.89) = 0.97062
Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .
The answer is going to be 7/8. hope that helped
Find two "dots" where the line crosses the X and Y axis at real numbers.
(0,3) and (6,-1)
Now find the slope which is the difference in Y over the difference in x.
Slope = (-1 - 3) / (6-0) = -4 / 6 = -2/3
The answer is D.