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ddd [48]
3 years ago
12

Find the complementary angles of the following.

Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0

Answer:

1. 87

A77

B24

C93

D47

E 31

F 48

2. 160

A10

B20

C30

D40

E 50

F 60

3. 68

A851

B295

C302

D574

E 112

F 638

4. 174

A3

B4

C5

D 6

E 7

F 8

5. a

A180-a

B180/2

C 179*a

D 179+a

E 60

F pi

Find the complementary angles of the following.

6. 53

A90

B32

C 25

D 45

E 18

F 37

7. 12

A46

B78

C98

D31

E 52

F 64

8. 73.5

A16.5

B34.2

C29.4

D17.7

E 57.9

F 11.3

9. 23.7

A66.3

B70.1

C42.5

D83.9

E 54.8

F 36.2

10. a

A90/a

Ba-90

Ca/2

D90-a

E 90-2

F a^2

Two of the angles are listed. Find the measure of the third angle in each triangle. Similar to example 6

11. 16,42

A256

B421

C107

D510

E 122

F 329

12. 90, 30

A23

B42

C47

D60

E 71

F 89

13. 43, 118

A12

B34

C19

D57

E 11

F 27

14. 60, 60

A15

B90

C29

D60

E 30

F 45

15. 14, 123

A73

B25

C38

D19

E 43

F 13

16. 68, 86

A45

B56

C26

D19

E 32

F 82

17. 55, 77

A18

B37

C62

D57

E 20

F 48

18. a, (a + 80)

A100 - 2a

B112 - 7a

C182 - 2a

D254 - 5a

E 311 - 3a

F 302 - 1a

19. x, (x + 20)

A189 - 7x

B167 - 1x

C114 - 5x

D160 - 2x

E 124 - 2x

F 142 - 1x

20. m, 2m

A172 - 2m

B187 - 7m

C124 - 4m

D143 - 1m

E 164 - 9m

F 180 - 3m

1. C

2. B

3. E

4. D

5. D

6. F

7. B

8. A

9. A

10. B

11. D

12. A

13. D

14. B

15. A

16. C

17. F

18. A

19. D

20. F

Step-by-step explanation:

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How do u write 5.6 as a fraction in simplest form
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The first answer to your question is 5 6/10 because you pronounce the decimal as six tenths. There is a simpler form of 5 6/10, it is 5 3/5. This is because you divide six by 2 and get 3 and divide 10 by two and get 5. 
5 0
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What is Add and Simply 7/4 + 5/6 =
Pani-rosa [81]
Simple, first find a common denominator, 24.

So,

7/4*6= 42/24
and
5/6*6=30/24

Then just add, 

42/24
+
30/24

Making it 72/24.

72/24=3

Thus, your answer is, 3.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%5Csqrt%7B5%7D" id="TexFormula1" title="3\sqrt{5}" alt="3\sqrt{5}" align="absmiddle" class="l
adoni [48]

Answer:

3/5???

Step-by-step explanation:

6 0
2 years ago
IQ is normally distributed with a mean of 100 and a standard deviation of 15. a) Suppose one individual is randomly chosen. Fin
nasty-shy [4]

Answer:

Step-by-step explanation:

Let X be the IQ

IQ is normally distributed with a mean of 100 and a standard deviation of 15.

a) the probability that this person has an IQ greater than 95

=P(X\geq 95)\\=P(Z\geq \frac{95-100}{15} \\=P(Z\geq -0.33)\\=0.1293+0.5\\=0.6293

=62.93%

b) the probability that this person has an IQ less than 125

=P(X\leq 125) =P(X\leq 1.67)\\=0.5-0.4525\\=0.0475

=4.75%

c) Sample size =500

P(X

No of people = 0.2486(500) =124.3

d) P(x>140)\\= P(Z>2.6)\\=0.5-0.4953\\=0.0047

No of persons = 0.0047(500) = 2.35

3 0
3 years ago
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