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Lunna [17]
3 years ago
9

You live in a big house. The master bathroom is 12 by 20 feet. Calculate the area of your bathroom.

Mathematics
2 answers:
Alla [95]3 years ago
5 0
(12)(20)= 240
The answer is going to be B. 240 sq ft
muminat3 years ago
4 0

Answer:

240 sq. ft

Step-by-step explanation:

Area = length * width

        = 12 *20

       = 240 sq. ft

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Elena-2011 [213]

Answer:

(40+4)+(40+48)

=40+(4+8)+4+8(40)

=44+48+12×40

if u add all

=104×40

=4160

Step-by-step explanation:

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2 years ago
Which numbers are solutions to the inequality x &lt; −7, using the replacement set {−15, −10.5, −7.2, −7, 0}?
slamgirl [31]
Find all the number in the set that are less than -7.

The 'bigger' the negative number seems, the smaller it is.

So -15, -10.5, and -7.2 are all less than -7.
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3 years ago
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Sally picked 815 flowers she wanted to put each flower in 4 pots how many more flowers does she pick so she won't gave any extra
bezimeni [28]

Answer:1 more flower

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Estimate by rounding to the nearest whole number 15-1/4 -4/5
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5 0
3 years ago
During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time
Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

\frac{dP}{dt} = Pr

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

\frac{dP}{P} = r dt

\int \frac{dP}{P} = \int r dt

\ln{P} = rt + K

Applying the exponential to both sides:

P(t) = Ke^{rt}

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

P(t) = 300e^{rt}

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

P(t) = 300e^{rt}

1000 = 300e^{24r}

e^{24r} = \frac{1000}{300}

e^{24r} = \frac{10}{3}

\ln{e^{24r}} = \ln{\frac{10}{3}}

24r = \ln{\frac{10}{3}}

r = \frac{\ln{\frac{10}{3}}}{24}

r = 0.05

So

P(t) = 300e^{0.05t}

At what time t is the population 500?

This is t for which P(t) = 500. So

P(t) = 300e^{0.05t}

500 = 300e^{0.05t}

e^{0.05t} = \frac{500}{300}

e^{0.05t} = \frac{5}{3}

\ln{e^{0.05t}} = \ln{\frac{5}{3}}

0.05t = \ln{\frac{5}{3}}

t = \frac{\ln{\frac{5}{3}}}{0.05}

t = 10.22

The population is of 500 after 10.22 hours.

7 0
3 years ago
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