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Sophie [7]
3 years ago
12

(02.01 LC)

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

Yes it is a function

Step-by-step explanation:

We have to check the ordered pairs to find out if given relation is a function or not.

In an ordered pair, the first element represents the input and the second element represents the output.

The set of inputs is domain and output is range.

For a relation to be function, there should be no repetition in domain i.e there should be unique pairs of input and output.

In the given relation, the domain is {3,5,-1,-2}.

No element is repeated hence it is a function ..

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Your answer is \frac{4}{9}

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An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and
egoroff_w [7]

Answer:

a) P(140

P(0.036

P(0.036

b) P(140< \bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(139,28.1)  

Where \mu=139 and \sigma=28.1

We are interested on this probability

P(140

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(140

And we can find this probability like this:

P(0.036

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(0.036

Part b

For this case we select a sample size of n =32. Since the distribution for X is normal then the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=139, \frac{\sigma}{\sqrt{n}}=\frac{28.1}{\sqrt{32}}=4.97)

And the new z score would be:

Z=\frac{\bar X -\mu}{\sigma_{\bar x}}

P(140< \bar X

P(140< \bar X

5 0
3 years ago
How do you do this?<br>please help if possible!
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6w - 17b = w
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(5/17)w = b

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7 0
3 years ago
Read 2 more answers
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GuDViN [60]

Answer:

2

Step-by-step explanation:

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x=2

6 0
3 years ago
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