Lexi has 24 students in her class 2/3 of the students are girls.how many girls are in lexis class?

Hi again here's the picture

pshichka [43]

Answer:

Step-by-step explanation:

Given,

D = diameter of semicircular part = 42 m

L = Length of straight part = 110 m

Now, let's find the perimeter:

= 2 ( length of semi-circle + length of straight part )

$= 2( \frac{\pi \: d}{2} + l)$

Plug the values

$= 2( \frac{3.14 \times 42}{2} + 110)$

Calculate the product

$= 2( \frac{131.88}{2} + 110)$

Divide

$= 2 (65.94 + 110)$

Calculate the sum

$= 2 \times 175.94$

Calculate

$= 351.88 \: m$

Hope this helps..

Best regards!!

8 0

3 years ago

Read 2 more answers

An equilateral triangle has side length 10 centimeters. Find its area in square centimeters. HINT: The altitude of an equilatera

dmitriy555 [2]

30cmsquared hope this helps!!!!!

3 0

3 years ago

A shirt has an original price of $19.75. If the shirt is marked 25% off and there is a 7.75% tax, how

Bumek [7]

Answer: 4.90 im not 100 percent sure

Step-by-step explanation:

To find the actual discount, multiply the discount rate by the original amount 'x'. To find the sale price, subtract the actual discount from the original amount 'x' and equate this to given sale price.

4 0

3 years ago

Read 2 more answers

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

irga5000 [103]

Answer:

The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let $C = (h,k)$ the coordinates of the center of the circle, which must be transformed into $C'=(h', k')$ by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

$(x-h)^{2}+(y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

$C''(x,y) = C(x, y) + U(x,y)$ (Eq. 1)

Where $U(x,y)$ is the translation vector, dimensionless.

If we know that $C(x, y) = (h,k)$ and $U(x,y) = (4, 0)$ , then:

$C''(x,y) = (h,k)+(4,0)$

$C''(x,y) =(h+4,k)$

2) <em>Reflection over the x-axis</em>:

$C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)]$ (Eq. 2)

Where $O(x,y)$ is the reflection point, dimensionless.

If we know that $O(x,y) = (h+4,0)$ and $C''(x,y) =(h+4,k)$ , the new point is:

$C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]$

$C'(x,y) = (h+4, 0)-(0,k)$

$C'(x,y) = (h+4, -k)$

And thus, $h' = h+4$ and $k' = -k$ . The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

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4 0

3 years ago

In a racing game, Austin has traveled 1,988 meters from the starting line. He's cruising with confidence when suddenly he slips

Korolek [52]

Answer:

1987.2

Step-by-step explanation:

7 0

3 years ago