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4 years ago

I need help on this

Mathematics

1 answer:

Komok [63]4 years ago

8 0

Answer:

I think that it is A or D

Step-by-step explanation:

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What is the slope of the line which passes through (−2, 0) and (0, 4)?

riadik2000 [5.3K]

Slope is rise/run, or y/x. So y from zero to 4 is 4, and x from -2 to zero is 2. and 4/2=2, so the slope is 2

5 0

4 years ago

Read 2 more answers

During his workouts last week, Allen jogged the same amount of time each day for 6 days. Use the following information to determ

Stella [2.4K]

So you have to break it down
Each workout he jogged and rode his bike
Everyday he jogged for for 45 minutes
He totaled 360 minutes for the week.

There are seven days in a week so divide the 360 by the 7 51 3/7 minutes everyday
Subtract 45 from it 6 3/7
So the answer is he jogged 6 minutes and around 26 seconds everyday
(Concert the 3/7 to seconds by my tip lying it by 60)

3 0

3 years ago

Read 2 more answers

Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten

serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

$\frac {dN}{dt}\propto -N$

$\Rightarrow \R\frac {dN}{dt}=-\lambda N$

$\Rightarrow \frac {dN}N=-\lambda dt$

Integrating both sides

$\Rightarrow \int \frac {dN}N=\int-\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$ln|N_0|=-\lambda .0+c$

$\Rightarrow c=ln|N_0|$

$ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$

Decay equation:

$ln|\frac{N}{N_0}|=-\lambda t$

Given that, the half life of of element X is 11 minutes.

For half life, $N=\frac12 N_0$ , t= 11 min.

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11$

$\Rightarrow ln|\frac12}|=-\lambda . 11$

$\Rightarrow -\lambda . 11=ln|\frac12}|$

$\Rightarrow \lambda =\frac{ln|\frac12|}{-11}$

$\Rightarrow \lambda =\frac{ln|2|}{11}$ [ $ln|\frac12|=ln|1|-ln|2|=-ln|2|$ , since ln|1|=0]

N=154 grams, $N_0$ = 870 grams, t=?

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t$

$\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}$

=27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0

3 years ago

Which expression could be used to find the circumference of the circle below?

spin [16.1K]

Answer:

Image result for Which expression could be used to find the circumference of the circle below?

Use the formula C = πd to find the circumference if you know the diameter. In this equation, "C" represents the circumference of the circle, and "d" represents its diameter. That is to say, you can find the circumference of a circle just by multiplying the diameter by pi.

Step-by-step explanation:

3 0

3 years ago

BASEBALL In the 2001 season, the Chicago Cubs won 88 out of 162 games. What percent of games did the Cubs win? Round to the near

jeyben [28]

Answer:

54%

Step-by-step explanation:

We have to divide 88/162.

We get 54.3% so 54%

8 0

3 years ago

I need help on this​

I need help on this