Answer:
14/20
Explanation:
Sasha tried to get a marble 20 times. 14 of those times she got a yellow marble.
The experimental probability, which is the probability of choosing a yellow marble when Sasha actually tries choosing marbles from the bag.
The theoretical probability is based on the chance that Sasha will get a yellow marble, 7/70, is from the amount of marbles in the bag of yellow colour.
The number of white sweatshirts is 28
Step-by-step explanation:
Let ordered black shirts be represented by b
Let ordered white shirts be represented by w
So total sweatshirts will be represented by the equation
b+w=50
The total cost of the ordered sweatshirts will be represented by
10b + 12 w= $556
For simultaneous equations as;
b+w=50
10b+12w=556
solving the equations using substitution method where b=50-w
10(50-w)+12w=556
500-10w+12w=556
-10w+12w=556-500
2w=56
w=56/2= 28
b=50-w=50-28=24
Number of white sweatshirts is 28
Learn More
Simultaneous equation :brainly.com/question/12919422
Keyword : cost
#LearnwithBrainly
We could use the Pythagorean theorem for this kind of problem I think:
A^2 + B^2 = C^2
6^2 + 16^2 = C^2
36 + 256 = C^2
292 = C^2
17.08 = C
C = 17.1 to the nearest tenth
Sorry if it’s wrong and glad I could help if it’s right ❤️❤️ Take care!
(p + q)⁵
(p + q)(p + q)(p + q)(p + q)(p + q)
{[p(p + q) + q(p + q)][p(p + q) + q(p + q)](p + q)}
{[p(p) + p(q) + q(p) + q(q)][p(p) + p(q) + q(p) + q(q)](p + q)}
(p² + pq + pq + q²)(p² + pq + pq + q²)(p + q)
(p² + 2pq + q²)(p² + 2pq + q²)(p + q)
{[p²(p² + 2pq + q²) + 2pq(p² + 2pq + q²) + q²(p² + 2pq + q²)](p + q)}
{[p²(p²) + p²(2pq) + p²(q²) + 2pq(p²) + 2pq(2pq) + 2pq(q²) + q²(p²) + q²(2pq) + q²(q²)](p + q)}
(p⁴ + 2p³q + p²q² + 2p³q + 4p²q² + 2pq³ + p²q² + 2pq³ + q⁴)(p + q)
(p⁴ + 2p³q + 2p³q + p²q² + 4p²q² + p²q² + 2pq³ + 2pq³ + q⁴)(p + q)
(p⁴ + 4p³q + 6p²q² + 4pq³ + q⁴)(p + q)
p⁴(p + q) + 4p³q(p + q) + 6p²q²(p + q) + 4pq³(p + q) + q⁴(p + q)
p⁴(p)+ p⁴(q) + 4p³q(p) + 4p³q(q) + 6p²q²(p) + 6p²q²(q) + 4pq³(p) + 4pq³(q) + q⁴(p) + q⁴(q)
p⁵ + p⁴q + 4p⁴q + 4p³q² + 6p³q² + 6p²q³ + 4p²q³ + 4pq⁴ + pq⁴ + q⁵
p⁵ + 5p⁴q + 10p³q² + 10p²q³ + 5pq⁴ + q⁵
