On a normally distributed anxiety test with mean 48 and standard deviation 4, approximately what anxiety test score would put so
1 answer:
Answer:
54.56
Step-by-step explanation:
Given:
Mean, u = 48
Standard deviation, = 4
Test score = 5%
Required:
Find the raw score, X.
Having a test score of 5% means the Zscore has to correspond to 95%, ie, 1 - 0.05 = 0.95.
Thus,
To get X, use the formula:
= 48 + (4 * 1.64)
= 48 + 6.56
= 54.56
The anxiety test score that would put someone in the top 5% is 54.56
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Using the asymptote concept, the function with a vertical asymptote at x = 3 and an horizontal asymptote at is given by:
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
The vertical asymptote at x = 3 means that x = 3 is a root of the denominator, hence:
The horizontal asymptote at y = -1/2 means that:
Which happens if , hence the function is:
More can be learned about asymptotes at brainly.com/question/16948935
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