On a normally distributed anxiety test with mean 48 and standard deviation 4, approximately what anxiety test score would put so
1 answer:
Answer:
54.56
Step-by-step explanation:
Given:
Mean, u = 48
Standard deviation, = 4
Test score = 5%
Required:
Find the raw score, X.
Having a test score of 5% means the Zscore has to correspond to 95%, ie, 1 - 0.05 = 0.95.
Thus,
To get X, use the formula:
= 48 + (4 * 1.64)
= 48 + 6.56
= 54.56
The anxiety test score that would put someone in the top 5% is 54.56
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Answer:
Morgan family picked 144 Braeburn apples, 96 Cortland apples, 72 Fuji apples and 48 Rome apples.
Step-by-step explanation:
Let B, C, F and R represent Braeburn apples, Cortland apples, Fuji apples, and Rome apples respectively.
We have been given that Morgan family picked a total of 360 apples. We can represent this information in an equation as:
We are told that Morgan family picked twice as many Braeburn as Fuji. We can represent this information in an equation as:
We are told that Morgan family picked twice as many Cortland as Rome, that is:
We are told that Morgan family picked 50% more Fuji than Rome, that is:
Upon substituting equation (4) in equation (2), we will get:
Now, each apple in in terms of Rome apples, so we will get:
Let us solve for R.
Therefore, Morgan family picked 48 Rome apples.
Upon substituting in (3), we will get:
Therefore, Morgan family picked 96 Cortland apples.
Upon substituting in (4), we will get:
Therefore, Morgan family picked 72 Fuji apples.
Upon substituting in (2), we will get:
Therefore, Morgan family picked 144 Braeburn apples.