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Tresset [83]
3 years ago
13

Solve the following system of equations: (5 points) 3x − 2y = 6 6x − 4y = 12

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0
<span>3x − 2y = 6 (1)
6x − 4y = 12 (2)
divide equation (2) by 2
3x - 2y = 6

equation (2) is same as equation 1
so answer is </span>infinitely many solutions
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Carlos purchased a bag of 455 marbles and he wants to distribute them equally to the 35 members in his class.
Gnoma [55]

Answer:13

Step-by-step explanation: Each classmate should get 13 marbles. To solve this simply divide 455 by 35.

3 0
3 years ago
My homework is Identify the terms, like terms, coefficients, and constants in each expression and I need the answers to n+5n, 12
AysviL [449]

Step-by-step explanation:

A term is a number, a variable, or a constant multiplied by a variable or variables.

Like terms are terms that contain the same variables raised to the same power. Only the numerical coefficients are different.

A coefficient is a multiplicative factor in some term of a polynomial (expression).

Constant is a term in the algebraic expression that contain only number.

n + 5n = n + 5n + 0

terms: n, 5n

like terms: n, 5n

coefficients: 1, 5

constant: 0

simplified form: n + 5n = 6n

term: 6n

coefficient: 6

constant: 0

=======================

12c - c = 12c - c + 0

terms: 12c, -c

like terms: 12c, -c

coefficients: 12, -1

constant: 0

simplified form: 12c - c = 11c

term: 11c

coefficient: 11

constant: 0

========================

-4j - 1 - 4j + 6

terms: -4j, -1, -4j, 6

like terms: -4j, -4j and -1, 6

coefficients: -4, -4

constants: -1, 6

simplified form: -4j - 1 - 4j + 6 = (-4j - 4j) + (-1 + 6) = -8j + 5

term: -8j, 5

coefficient: -8

constant: 5

7 0
4 years ago
What is the total area of the regions between the curves y = 6x2 − 18x and y = −6x from x = 1 to x=3?.
kvasek [131]

Using integration, it is found that the area between the two curves is of 22 square units.

<h3>What is the area between two curves?</h3>

The area between two curves y = f(x) and y = g(x), in the interval from x = a to x = b, is given by:

A = \int_{x = a}^{x = b} |f(x) - g(x)| dx

In this problem, we have that:

f(x) = 6x^2 - 18x, g(x) = -6x, a = 1, b = 3.

Hence, the area is:

A = \int_{1}^3 |6x^2 - 12x| dx

A = |x^3 - 6x^2|_{x = 1}^{x = 3}

Applying the Fundamental Theorem of Calculus:

A = |3^3 - 54 - 1^3 + 6|

A = 22

The area between the two curves is of 22 square units.

More can be learned about the use of integration to find the area between the two curves at brainly.com/question/20733870

8 0
3 years ago
Due today pls helppppp
LiRa [457]
<h3>Answer:   19.1</h3>

====================================================

Work Shown:

tan(angle) = opposite/adjacent

tan(C) = AB/BC

tan(theta) = x/BC

tan(23) = (8.1)/BC

BC*tan(23) = 8.1

BC = (8.1)/tan(23)

BC =  19.0824041631723

BC = 19.1

In this case, rounding to 3 sig figs means we round to the nearest tenth.

Make sure your calculator is in degree mode.

3 0
3 years ago
What is the slope of the line?<br> $<br> 2<br> 45<br> 6&gt;x<br> -3
Nikitich [7]

Step-by-step explanation: i am pretty sure it is 1

4 0
4 years ago
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