First, find the z-score:
z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33
In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)
Looking at the table, we find P(z < 0.33) = 0.6293
Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707
Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
Answer:
The given information tells us that AFD is either an equilateral or isosceles triangle. We can see by the diagram that it is not equilateral, so the correct answer here would be the second one, "Isosceles".
So the equaiton is
number of nickes=n
number of quarters=q
if you have 1 quarter then you have 25 cents so we will represent like this
25q
and nickles is 5n
14.50=1450 cents
so
25q+5n=1480
q+n=88
subtract q from both sides
n=88-q
subsitute into first equation
25q+5(88-q)=1480
25q+440-5q=1480
add like terms
20q+440=1480
subtract 440 from both sides
20q=1040
divide both sdies by 20
q=52
there were 52 quarters
25(52)+5n=1480
1300+5n=1480
subtract 1300 from both sides
5n=180
divide both sides by 5
n=36
there were 36 nickels
nickles=36
quarters=52
Answer:
The exponent of the second term (b) starts with 0 (b0 = 1) and then increases by one in each following term until it is equal to the exponent of the binomial (5).
Step-by-step explanation:
<u>ANSWER: </u>
The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).
<u>SOLUTION:
</u>
Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).
Let us first solve the above equations using <em>elimination process.
</em>
For elimination, one of the coefficients of variables has to be same in order to cancel them.
Now solve (1) and (2)
eqn (1) 
2 → 4x + 6y = 10
eqn (2) → 4x – y = 17
(-) ----------------------------
0x + 7y = -7
y = -1
Substitute y value in (2)
So, solution of two equations is (4, -1).
<u><em>Now let us solve using substitution process.</em></u>
Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17
Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56
x = 4
Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1
Hence, the solution of the two equations is (4, -1).
