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kirill115 [55]
3 years ago
7

Sam left his school at 3:05. He walked at a speed of 3.2 mph. 15 minutes later, Al started running after him, and he caught up w

ith Sam 10 minutes later. What was Al’s speed? Answer:
Mathematics
1 answer:
KonstantinChe [14]3 years ago
5 0
Total time taken by Sam before Al caught up with him = 15+10 = 25 minutes

In hours = 25 minutes = 25/60 = 5/12 hrs
Distance covered by Sam = Distance covered by Al = Speed (Sam) * time taken = 3.2*5/12 = 4/3 miles.

Al takes 10 minutes to cover that distance. Therefore,
Al's speed = Distance/time = (4/3)/(10/60) = (4/3)*(60/10) = 8 mph
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