Answer and work down below. Let me know if you have any questions
Answer:
Step-by-step explanation:
Statements Reasons
1). SP ≅ TP 1). Given
2). PQ bisects ∠SPT 2). Given
3). ∠SPQ ≅ ∠TPQ 3). Definition of angles bisector
4). PQ ≅ PQ 4). Reflexive property of congruence
5). ΔSPQ ≅ ΔTPQ 5). SAS property of congruence
Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
Answer: 32
Step-by-step explanation: