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3 years ago

How many decimeters are in 3.5 dekameters? Use the metric table to help answer the question.

Mathematics

1 answer:

Ivahew [28]3 years ago

5 0

350 decimeters are there in 3.5 decameter

Solution:

We have to find the decimeters in 3.5 decameters

Use the metric table:

1 kilometre (km) = 10 Hectometres (hm) = 1000 m

1 Hectometre (hm) = 10 Decametres (dcm) = 100 m

1 Decametre (dcm) = 10 Metres (m)

1 Metre (m) = 10 Decimetres (dm) = 100 cm = 1000 mm

1 Decimetre (dm) = 10 Centimetres (cm)

1 decimeter = 0.1 meter

1 Centimetre (cm) = 10 Millimetres (mm)

1 centimeter = 0.01 meter

1 millimeter = 0.001 meter

From above metric table, we find that

100 decimeter = 1 decameter

Then, convert 3.5 decameter to decimeter

100 x 3.5 decimeter = 3.5 x 1 decameter

350 decimeter = 3.5 decameter

Thus 350 decimeters are there in 3.5 decameter

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3 years ago

Change the equation to slope intercept form and identity the slope and y-intercept -8x+2y=6

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The answer is:

$y=4x+3$

The slope is: 4

The y-intercept is: 3

The explanation is shown below:

1. The slope intercept form of the linear equation is:

$y=mx+b$

Where $m$ is the slope and $b$ is the y-intercept.

2. Therefore, you must solve for y, as following:

$-8x+2y=6\\y=\frac{8x+6}{2}\\y=4x+3$

$m=4\\b=3$

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3 years ago

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At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

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3 years ago

Given the function f(x) = | -2x + 4 |. Complete the table.

Finger [1]

Answer:

See below.

Step-by-step explanation:

To complete the table, start by copying the given function.

f(x) = |-2x + 4|

Now let's start with the first line of the table: x = 6.

You are finding the value of function f when x = 6.

Replace x with 6 and evaluate the expression.

f(6) = |-2(6) + 4|

f(6) = |-12 + 4|

f(6) = |-8|

f(6) = 8

Second line of table:

x = -1

f(x) = |-2x + 4|

f(-1) = |-2(-1) + 4|

f(-1) = |2 + 4|

f(-1) = |6|

f(-1) = 6

For the third and fourth lines, you are given a y value, or the value of function f, and you are looking for x. Now you use the given value to set the function equal to, and you solve for x.

Line 3: f(x) = 4

f(x) = |-2x + 4|

|-2x + 4| = 4

-2x + 4 = 4 or -2x + 4 = -4

-2x = 0 or -2x = -8

x = 0 or x = 4

Line 4: f(x) = 14

f(x) = |-2x + 4|

|-2x + 4| = 14

-2x + 4 = 14 or -2x + 4 = -14

-2x = 10 or -2x = -18

x = -5 or x = 9

The table looks like this:

x f(x)

6 8

-1 6

0,4 4

-5, 9 14

$\end{center}$

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3 years ago

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Answer:

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Step-by-step explanation:

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