3(x - 2) + 2 = 5(x - 3) + 9 por fa

Mathematics

1 answer:

hram777 [196]3 years ago

5 0

Answer:

x = 1

Step-by-step explanation:

Given

3(x - 2) + 2 = 5(x - 3) + 9 ← distribute and simplify both sides

3x - 6 + 2 = 5x - 15 + 9

3x - 4 = 5x - 6 ( subtract 5x from both sides )

- 2x - 4 = - 6 ( add 4 to both sides )

- 2x = - 2 ( divide both sides by - 2 )

x = 1

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express the limit as a definite integral on the given interval. lim n → [infinity] n ∑ i = 1 cos x i x i δ x , [ 2 π , 4 π ]

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The limit as a definite integral on the interval $\lim _{n \rightarrow \infty} \sum_{i=1}^n \frac{\cos x_i}{x_i} \Delta x$ on [2π , 4π] is $\int_{2\pi}^{4 \pi} \frac{\cos x}{x} d x$$ .

<h3>What is meant by definite integral?</h3>

A definite integral uses infinitesimal slivers or stripes of the region to calculate the area beneath a function. Integrals can be used to represent a region's (signed) area, the cumulative value of a function changing over time, or the amount of a substance given its density.

Definite integral, a term used in mathematics. is the region in the xy plane defined by the graph of f, the x-axis, and the lines x = a and x = b, where the area above the x-axis adds to the total and the area below the x-axis subtracts from the total.

If an antiderivative F exists for the interval [a, b], the definite integral of the function is the difference of the values at points a and b. The definite integral of any function can also be expressed as the limit of a sum.

Let the equation be

$\int_a^b f(x) d x=\lim _{n \rightarrow \infty} \sum_{i=1}^n f\left(x_i\right) \Delta x$