we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
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Answer:
2 or 2/1
Step-by-step explanation:
<u>Rise</u> = <u>2</u>
Run = 1
For the first one I’m not sure, but for 2 it is B and 3 is 5.
Answer:
![(7x)^{\frac{2}{3} = (\sqrt[3]{7x})^2](https://tex.z-dn.net/?f=%20%287x%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%3D%20%28%5Csqrt%5B3%5D%7B7x%7D%29%5E2%20)
Step-by-step explanation:
Given the expression
, to express this as a radical expressions, we'd apply the rule/law of indices that deals with converting expressions that has rational exponents into radical expressions.
The rule of indices to apply is: ![b^{\frac{m}{n}} = (\sqrt[n]{b})^m](https://tex.z-dn.net/?f=%20b%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%20%28%5Csqrt%5Bn%5D%7Bb%7D%29%5Em%20)
To apply this to the expression,
, the denominator of the fraction of the exponent would determine the root, that is, cube root in this case. The numerator of the exponent would then determine the exponent of the radical expressions.
Thus:
![(7x)^{\frac{2}{3} = (\sqrt[3]{7x})^2](https://tex.z-dn.net/?f=%20%287x%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%3D%20%28%5Csqrt%5B3%5D%7B7x%7D%29%5E2%20)
A
B or D is your answer
Hope this helps
Step-by-step explanation: