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3 years ago

6

A friend asks to borrow $250 for 18 months and agrees to pay 12% annual simple interest. How much interest will you earn? Round

your answer to the nearest dollar.

1 answer:

german3 years ago

7 0

Answer: $29.70

Step-by-step explanation:

250 times the annual interest (12%) is converted to 250 times .12 = 29.70

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Simplify and write answer in standard form.

mamaluj [8]

Answer:

$x^3+8x^2+2x+1$

Step-by-step explanation:

Combine like terms (terms with the same exponent).

$x^3+(3x^2+5x^2)+(x+x)+1=x^3+8x^2+2x+1$

"Standard form" means to list terms so the exponents go from high to low (descending order).

6 0

3 years ago

The ratio of the perimeter of two similar polygons is 5:7. The area of the smaller polygon is 30 sq. cm. Find the area of the la

Debora [2.8K]

Answer:

42sq

Step-by-step explanation:

5:7

30 sq: x sq

30/5=6 sq for 1 of the ratio

6*7=42 sq for 7 of the ratio

4 0

3 years ago

one side of a ship has marks spaced 3 feet apart. four marks are underwater. how many feet of the ship are underwater

anastassius [24]

A boat has a ladder that has six rungs. Each rung is one foot apart. The bottom rung is one foot from the water. The tide rises at 12 inches every 15 minutes

7 0

3 years ago

Would someone help me 2/3 2/1 8/9 7/9 breast to least

Tema [17]

Answer:

First of all, it's the Greatest to least! Second of all, 2/1, 8/9, 7/9, and 2/3.

Step-by-step explanation:

2/1 is 2, 8/9 is 1 more ninth than 7/9, and 2/3 is less third than 1.

4 0

2 years ago

Read 2 more answers

The daily revenues of a cafe near the university are approximately normally distributed. The owner recently collected a random s

lbvjy [14]

Answer:

The sample size to obtain the desired margin of error is 160.

Step-by-step explanation:

The Margin of Error is given as

$MOE=z_{crit}\times\dfrac{\sigma}{\sqrt{n}}$

Rearranging this equation in terms of n gives

$n=\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2$

Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as

$n_2=\left[z_{crit}\times \dfrac{\sigma}{M_2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{\sigma}{M/2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{2\sigma}{M}\right]^2\\n_2=2^2\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4n$

As n is given as 40 so the new sample size is given as

$n_2=4n\\n_2=4*40\\n_2=160$

So the sample size to obtain the desired margin of error is 160.

4 0

3 years ago