Ask question

Ask question

All categories

Free_Kalibri [48]

2 years ago

5

HELP MEEEEEEEEEE SOOOOOO EASY PLEASE AND BRANLIEST TOOOOOO (07.04 LC)What is the solution to the equation fraction 1 over 3x = 6

?
x = 18
x = 2
x = fraction 1 over 2
x = fraction 1 over 18

2 answers:

nasty-shy [4]2 years ago

7 0

Answer:

<em>x = 2</em>

<em>divide each term by 3 and simplify.</em>

madam [21]2 years ago

7 0

Answer:

I did the quiz and it is B

Step-by-step explanation:

You might be interested in

A quantity p varies jointly with r and s. Which expression represents the constant of variation, k?

Zina [86]

The correct answer is p/rs.

In order to find this first state the direct variation with the constant k included.

p = krs

Now to find the value of k, we simply divide away the r and s

p/rs = k

3 0

2 years ago

Read 2 more answers

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0

2 years ago

A new club sent out 288 coupons to boost sales for next year's memberships. They provided 5 times as many to potential members t

Aliun [14]

Answer:

D. 48

Step-by-step explanation:

We don't know the numbers of coupons sent to existing members and to potential members, but we know a relationship between the number.

They sent 5 times as many coupons to potential members as they did to existing members.

Let x = number of coupons sent to existing members.

Then 5x = number of coupons sent to potential members.

The total number of coupons sent was x + 5x = 6x

The total number of coupons sent was 288.

Therefore, 6x must equal 288 giving us an equation with a single variable.

6x = 288

x = 48

Answer: 48

7 0

2 years ago

Find an equation of the line satisfying the given conditions Through (6,4); perpendicular to 3X + 5Y =38

Katyanochek1 [597]

To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the

First, we will need to find the slope of this equation. To find this, we must simplify the equation $3x+5y=38$ into $y=mx+b$ form. Lets do it!

$3x+5y=38$
= $5y = -3x+38$ (Subtract 3x from both sides)
= $y= -\frac{3}{5}x+ \frac{38}{5}$ (Divide both sides by 5)

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is $\frac{5}{3}$ .

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

$\frac{y-y _{1} }{x- x_{1} }=m$

Substituting values, we find that:

$\frac{y-4}{x-6}= \frac{5}{3}$

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that:

$y= \frac{5}{3}x-6$ , which is our final answer.

Thank you, and I wish you luck.

8 0

3 years ago

Read 2 more answers

For which equation would x = 0 be a solution?

Vesna [10]

Answer:

x/9.074

Step-by-step explanation:

this is the equation that gives the correct answer

0/9.074=0

6 0

2 years ago