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Free_Kalibri [48]

3 years ago

5

HELP MEEEEEEEEEE SOOOOOO EASY PLEASE AND BRANLIEST TOOOOOO (07.04 LC)What is the solution to the equation fraction 1 over 3x = 6

?
x = 18
x = 2
x = fraction 1 over 2
x = fraction 1 over 18

2 answers:

nasty-shy [4]3 years ago

7 0

Answer:

<em>x = 2</em>

<em>divide each term by 3 and simplify.</em>

madam [21]3 years ago

7 0

Answer:

I did the quiz and it is B

Step-by-step explanation:

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A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

3 years ago

£50 is worth €65 how many euros is £220 worth

Cloud [144]

Answer:

£220 is worth €247

4 0

3 years ago

Find AB.<br> Round to the nearest tenth.<br> 61°

anzhelika [568]

Answer:

AB ≈ 14.3

Step-by-step explanation:

We're given <em>two sides </em>(BC and CA) and an <em>angle </em>(C)<em> between them</em>; the <em>law of cosines </em>is a good tool for calculating the third side of the triangle here. To remind you, the law of cosines tells us the relationship between the sides of a triangle with side lengths a, b, and c:

$c^2=a^2+b^2-2ab\cos{C}$

Where C is the angle between sides a and b. c is typically the side we're trying to find, so on our triangle, we have

$c=AB\\a=BC=16\\b=CA=5\\C=m\angle C=61^{\circ}$

Substituting these values into the law of cosines:

$c^2=16^2+5^2-2(16)(5)\cos{61^{\circ}}\\c^2=256+25-160\cos{61^{\circ}}\\c^2=281-160\cos{61^{\circ}}\\c=\sqrt{281-160\cos{61^{\circ}}}\\c\approx 14.3$

6 0

4 years ago

Read 2 more answers

For every 1 girl in Mr hegarty’s class there are 2 boys. What is the ratio of girls to boys in the class? Give the answer in sim

svetoff [14.1K]

1:2 i believe good luck

8 0

3 years ago

Read 2 more answers

10=z+6<br>Plz help me with this

garik1379 [7]

Answer:

z=4

Step-by-step explanation:

6+4=10

6 0

4 years ago