(x-yi)(3+5i) is the conjugate of 6+24i

Mathematics

1 answer:

Nataly_w [17]3 years ago

5 0

Answer:

x=-3

y=3

(-3-3i)(3+5i)

Step-by-step explanation:

$(x-yi)(3+5i)\\=3x+5xi-3yi+5y\\=(3x+5y)+(5x-3y)i\\$

and we have that must equal

6-24i

3x+5y=6

5x-3y=-24 and if we work it we found out that the solutions are

x=-3 and

y=3

You might be interested in

Simplify 6log6 15 A. 4.701849846e+11 B. 90 C. 15 D. 6

Rama09 [41]

$\begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} \\\\\\ \textit{Logarithm Change of Base Rule} \\\\ \log_a b\implies \cfrac{\log_c b}{\log_c a}\qquad \qquad c= \begin{array}{llll} \textit{common base for }\\ \textit{numerator and}\\ denominator \end{array} \\\\[-0.35em] ~\dotfill$

$6\log_6(15)\implies \log_6(15^6)\implies \stackrel{\textit{change of base rule}}{\cfrac{\log_{10}(15^6)}{\log_{10}(6)}}\qquad \approx \qquad 9.068\qquad \approx\qquad 9$