−3x + 6 = 5 | -6 (first step is: "subtract 6 from both sides" )

-3x = 5-6
-3x = -1 | /(-3) (second step is: "divide by (-3) on both sides" )

 $\displaystyle \\ 
x = \frac{-1}{-3} = \boxed{\frac{1}{3} }$

5 0

3 years ago

Read 2 more answers

Do i use SIN, COS, or TAN to find the missing lengths?

BaLLatris [955]

Answer:

Step-by-step explanation:

+ Because of a right triangle, so we can find them- the missing lengths:

+ sin(40)= GH/GF

so GH = GF * sin(40) = 88* sin (40) = 56.565= GH

+ cos( 40) = FH/GF

so FH= GF *cos(40)= 88* cos(40) = 67.412= FH

Have a good day

3 0

3 years ago

Please help with this question

natita [175]

Answer:

$12\sin{(2\theta)}\cos{(\theta)}$

Step-by-step explanation:

The appropriate trig identity is ...

$\sin{a}+\sin{b}=2\sin{\left(\dfrac{a+b}{2}\right)}\cos{\left(\dfrac{a-b}{2}\right)}$

Here, you have a scale factor of 6 and a=3θ, b=θ. Filling in these values gives ...

$6\sin{3\theta}+6\sin{\theta}=12\sin{\left(\dfrac{3\theta+\theta}{2}\right)}\cos{\left(\dfrac{3\theta-\theta}{2}\right)}\\\\=12\sin{(2\theta)}\cos{(\theta)}$

8 0

3 years ago

Identify the side lengths of the triangle.

Degger [83]

Answer:

36 36 32

Step-by-step explanation:

6 0

3 years ago