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adelina 88 [10]
2 years ago
7

A supermarket needs to display 64 boxes of detergent.

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
5 0
  • All the listed combination of row and boxes are correct and can be chosen from.

From the question, we are asked to find the row arrangement of a stack of boxes. Let us take a look at each one of the aforelisted answers

  • x rows with 16 boxes in each row
  • 8 rows with x boxes in each row
  • 16 rows with x boxes in each row

Since we are told that the total number of boxes to be stacked is 64, then for the first arrangement, we can deduce that the "x" is going to be 4. This is because multiplying 4 by 16 gives 64. For the second row, using the same calculation, we find that "x" is 8. And that of the third gives our "x" to be 4 as well. We can then adjudge that;

  • 4 rows with 16 boxes in each row
  • 8 rows with 8 boxes in each row
  • 16 rows with 8 boxes in each row

Bearing this in mind, we can see that each of the 3 answers fits into the requirements we are asked.

  • At least 3 rows, and at least 4 boxes in each row.

Hence, all of the options are correct.

To learn more about rows and columns, see here brainly.com/question/13196178

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Adding fractions 1/6+2/3=
mars1129 [50]

Answer:

\frac{5}{6}

\frac{1}{6} + \frac{2}{3} is equivalent to \frac{1}{6} + \frac{4}{6}.

This is because \frac{2}{3}=\frac{4}{6}

The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

<em>Now what do we do? We add!</em>

\frac{1}{6} + \frac{4}{6} =\frac{5}{6}

This is because 4 + 1 = 5.

Your answer is \frac{5}{6}.

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
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Which is a valid prediction about the continuous function f(x)?
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Without seeing the graph, it's impossible to tell. The same can be said if we don't know the function rule. However, we can rule out three non-answers. 

Choice B is false because the interval [1,3] has f(x) below zero but the rest of the interval to the right of x = 3 has f(x) not below zero.

Choice C is false. The value x = -1 leads to f(x) = 0 which is not greater than 0

Choice D is false because the values 8 and 4 are positive

After eliminating B, C, & D, we are left with choice A as the answer.
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Point 6,8 lies in which quadrant
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Answer:

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Find the center and radius when x^2+y^2+4x-4y=17
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Write the polynomial f(x)=x^4-10x^3+25x^2-40x+84. In factored form
Verizon [17]
<h2>Steps:</h2>

So firstly, to factor this we need to first find the potential roots of this polynomial. To find it, the equation is \pm \frac{p}{q}, with p = the factors of the constant and q = the factors of the leading coefficient. In this case:

\textsf{leading coefficient = 1, constant = 84}\\\\p=1,2,3,4,6,7,12,14,21,28,42,84\\q=1\\\\\pm \frac{1,2,3,4,6,7,12,14,21,28,42,84}{1}\\\\\textsf{Potential roots =}\pm 1, \pm 2,\pm 3,\pm 4,\pm 6, \pm 7,\pm 12,\pm 14,\pm 21,\pm 28,\pm 42,\pm 84

Next, plug in the potential roots into x of the equation until one of them ends with a result of 0:

f(1)=(1)^4-10(1)^3+25(1)^2-40(1)+84\\f(1)=1-10+25-40+84\\f(1)=60\ \textsf{Not a root}\\\\f(2)=2^4-10(2)^3+25(2)^2-40(2)+84\\f(2)=16-10*8+25*4-80+84\\f(2)=16-80+100-80+84\\f(2)=80\ \textsf{Not a root}\\\\f(3)=3^4-10(3)^3+25(3)^2-40(3)+84\\f(3)=81-10*27+25*9-120+84\\f(3)=81-270+225-120+84\\f(3)=0\ \textsf{Is a root}

Since we know that 3 is a root, this means that one of the factors is (x - 3). Now that we know one of the roots, we are going to use synthetic division to divide the polynomial. To set it up, place the root of the divisor, in this case 3 from x - 3, on the left side and the coefficients of the original polynomial on the right side as such:

  • 3 | 1 - 10 + 25 - 40 + 84
  • _________________

Firstly, drop the 1:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓
  • _________________
  •     1

Next, multiply 3 and 1, then add the product with -10:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3
  • _________________
  •     1  - 7

Next, multiply 3 and -7, then add the product with 25:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3  - 21
  • _________________
  •     1  - 7 + 4

Next, multiply 3 and 4, then add the product with -40:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3  - 21 + 12
  • _________________
  •     1  - 7  +  4  - 28

Lastly, multiply -28 and 3, then add the product with 84:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3  - 21 + 12  - 84
  • _________________
  •     1  - 7  +  4  - 28 + 0

Now our synthetic division is complete. Now since the degree of the original polynomial is 4, this means our quotient has a degree of 3 and follows the format ax^3+bx^2+cx+d . In this case, our quotient is x^3-7x^2+4x-28 .

So right now, our equation looks like this:

f(x)=(x-3)(x^3-7x^2+4x-28)

However, our second factor can be further simplified. For the second factor, I will be factoring by grouping. So factor x³ - 7x² and 4x - 28 separately. Make sure that they have the same quantity inside the parentheses:

f(x)=(x-3)(x^2(x-7)+4(x-7))

Now it can be rewritten as:

f(x)=(x-3)(x^2+4)(x-7)

<h2>Answer:</h2>

Since the polynomial cannot be further simplified, your answer is:

f(x)=(x-3)(x^2+4)(x-7)

6 0
3 years ago
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