Question

Identify the surface whose equation is given. rho2(sin2(φ) sin2(θ) + cos2(φ)) = 49

Answer 1

Answer:

The surface is a cylindrical surface with radius 7 units

Step-by-step explanation:

The equation is properly written as:

$\rho^{2} (sin^{2} \phi sin^{2} \theta + cos^{2} \phi) = 49$

The above equation takes the form $y^{2} + z^{2} = r^{2}$

Where $y^{2} = \rho^{2} sin^{2} \phi sin^{2} \theta$

$y = \rho sin \phi sin \theta$

and $z^{2} = \rho^{2}cos^{2} \phi$

$z = \rho cos \phi$

$r^{2} = 49$

r = 7 units

The surface is a cylindrical surface with radius 7 units