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Cerrena [4.2K]
3 years ago
13

I have exams coming up and I have a question say hypothetically you have a 71.69% as a grade and you fail your exam which is 10%

of you’re grade what would be you’re over all score. Also could you also tell me what it would be if the exam is 20% if you’re grade?
Mathematics
1 answer:
Alona [7]3 years ago
7 0

Answer:

If you received a 0 for the grade, 10% of 71.69 is 7.169; simply subtract 71.69-7.169 to get 64.521 rounds to 64.52. If 20% then the answer is 57.36.

Step-by-step explanation:

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Sonja [21]
To find the amount of soup in the soup-milk mixture, we just need to subtract the amount of milk from the amount of soup-milk mixture.

2 5/8 - 1 1/3 = 1 7/24.

There were 1 7/24 cups of soup in the can.
Hope that helped =)
8 0
3 years ago
PLEASE HELP ITS IXL ​
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On Kathleen's credit card statement get last balance was $89.70. She made a payment of $20, had new charges totaling $32.11, and
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Hi there

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5 0
3 years ago
<A and <J are complementary angles. Find the value of x m<A = 5x + 30 m<J = 4x +15
uranmaximum [27]

Sum of complementary angles always equal to 90°.

Given, <A and <J are complementary angles. So, we can set up an equation as following:

m<A+ M<J= 90

Next step is to plug in m<A = 5x + 30 and m<J = 4x +15 in the above equation. So we will get,

5x+30+4x+15=90

(5x+4x)+(30+15)=90 Group the like terms.

9x+45=90 Combine the like terms.

9x+45-45=90-45 Subtract 45 from each sides.

9x=45 By simplifying.

\frac{9x}{9}=\frac{45}{9} Divide each sides by 9.

x=5.

So, x=5.

8 0
3 years ago
two towers labeled Tower A and Tower B some distance apart and a fire image at a certain distance from both towers Towers A and
astra-53 [7]

Answer:

7.0 mi

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

substitute the given values

42^o+64^o+C=180^o\\C=180^o-106^o=74^o

step 2

Find the measure of a

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{10}{sin(74^o)}=\frac{a}{sin(42^o)}

solve for a

a=\frac{10}{sin(74^o)}sin(42^o)\\a=7.0\ mi

8 0
3 years ago
Read 2 more answers
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