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fredd [130]
3 years ago
14

What is the result of segmenting a network with a bridge (switch)? (Choose two)

Computers and Technology
1 answer:
Ronch [10]3 years ago
7 0

Answer: (D) It makes smaller collision domain and (F) It increases the number of collision domains.

Explanation:

  The result of segmenting a given network with the bridge is that it basically break the domain of the collision that increases the domain number. In additionally, it also makes it more smaller.  

Switch basically expands the quantity of collision network domain in the system. Switches are designed with V-LANs will diminish the given size of domain of the collision by increasing the number of the collision domain in the network.  

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lapo4ka [179]

Answer:

from datetime import time, datetime, timedelta, date

for _ in iter(list, 0):

   t1 = input("Please enter time one: ")

   t2 = input("Please enter time two: ")

   if t1.isdigit() == True and (int(t1[:2])<=23 and int(t1[2:]) <= 59)\

       and t2.isdigit() == True and (int(t2[:2])<= 23 and int(t2[2:])<=59):

       time_1 = time(hour=int(t1[:2]), minute=int(t1[2:]))

       time_2 = time(hour= int(t2[:2]), minute=int(t2[2:]))

       if time_1 > time_2:

           diff = datetime. combine (date. today( ), time_1) - datetime. combine(date. today ( ), time_2)

       else:

           diff = datetime. combine (date. today( ), time_2) -datetime. combine(date. today ( ), time_1)

       diff_list = str(diff).split(":")

       del diff_list[2]

       diff_t = "". join (diff_list)

       print(diff_t)

       break        

   if t1.isdigit() == False or t2.isdigit() == False:

       print("Military Time Forest Required: Bad input, try again.")

       continue

   elif int(t1[:2])> 23 or int(t2[:2])> 23:

       print("Military Tine Format Required: Hours must be between 00 and 23, try again")

       continue

   elif int(t1[2:])> 59 or int(t2[2:])> 59:

       print("Military Tine Format Required: Minutes must be between me and 59, try again")

       continue

Explanation:

The python Datetime package is used to manipulate date and time, creating immutable Datetime objects from the various python data types like integer and string. The block of code above is a conditional for-loop statement that gets two user time value inputs and prints out the difference as a string in Military forest time format.

5 0
3 years ago
Half of the integers stored in the array data are positive, and half are negative. Determine the
jonny [76]

Answer:

Check the explanation

Explanation:

Below is the approx assembly code for above `for loop` :-

1). mov ecx, 0

2). loop_start :

3).    cmp ecx, ARRAY_LENGTH

4).    jge loop_end

5).    mv temp_a, array[ecx]

6).    cmp temp_a, 0

7).    branch on nge

8).        mv array[ecx], temp_a*2

9).   add ecx, 1

10).   jmp loop_start

11). loop_end :

Assumptions :-

*ARRAY_LENGTH is register with value 1000000

*temp_a is a register

Frequency of statements :-

1) will be executed one time

3) will be executed 1000000 times

4) will be executed 1000000 times

5) will be executed 1000000 times

6) will be executed 1000000 times

7) `nge` will be executed 1000000 times, branch will be executed 500000 times

8) will be executed 500000 times

9) will be executed 1000000 times

10) will be executed 1000000 times

Cost of statements :-

1) 10 ns

3) 10ns + 10ns + 10ns [for two register accesses and one cmp]

4) 10ns [for jge ]

5) 10ns + 100ns + 10ns [10ns for register access `ecx`, 100ns for memory access `array[ecx]`, 10ns for mv]

6) 10ns + 10ns [10ns for register_access `temp_a`, 10ns for mv]

7) 10ns for nge, 10ns for branch

8) 30ns + 110ns + 10ns

10ns + 10ns + 10ns for temp_a*2 [10ns for moving 2 into a register, 10ns for multiplication],

110ns for array[ecx],

10ns for mv

9) 10ns for add, 10ns for `ecx` register access

10) 10ns for jmp

Total time taken = sum of (frequency x cost) of all the statements

1) 10*1

3) 30 * 1000000

4) 10 * 1000000

5) 120 * 1000000

6) 20 * 1000000

7) (10 * 500000) + (10 * 1000000)

8) 150 * 500000

9) 20 * 1000000

10) 10 * 1000000

Sum up all the above costs, you will get the answer.

It will equate to 0.175 seconds

7 0
3 years ago
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