Answer:
x = -3, 6
Step-by-step explanation:
First, add 18 to both sides
x² - 3x - 18 = 0
+ 18 + 18
x² - 3x = 18
Add 9/4 to both sides because that is the square of half of -3
x² - 3x + 9/4 = 18 + 9/4
Multiply both sides by 4 to get rid of the fractions
(x² - 3x + 9/4 = 18 + 9/4)4
4x² - 12x + 9 = 72 + 9 = 81
Factor the left side of the equation
(2x - 3)² = 81
√(2x - 3)² = √81
Because of the square root, this will result in a positive number and a negative number
2x - 3 = 9
2x - 3 = -9
For both equations, add 3 to both sides then divide by 2
2x - 3 = 9
+ 3 +3
2x = 12
2x/2 = 12/2
x = 6
2x - 3 = -9
+ 3 + 3
2x = -6
x = -3
Given that <span>|x| + y ≥ 0, this means that y ≥ -|x|
Because |x| is always positive, then -|x| will always be negative.
The correct graph is the second graph.
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The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:
X² - 5x + 4 = 0
Factor the equation:
(x - 1)(x - 4) = 0
Now calculate each piece separately, starting with the first one:
x - 1 = 0
Add 1 to both sides of the equation:
x = 1
We have proven that x = 1. Now calculate the second piece:
x - 4 = 0
Add 4 to both sides of the equation:
x = 4
We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.
I hope this helps!
The correct answer would be 128.
