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sergejj [24]
3 years ago
15

Can somebody help me do this?

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

a) Point Q

b) Sides SQ,RQ

c)Angle RQT and Angle Q

Step-by-step explanation:

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mylen [45]
The answer is 40 degrees
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3 years ago
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A model of a famous statue is 2 1/2 inches tall. The actual statue is 3 1/3 feet tall. What is the ratio of the height of the mo
Gekata [30.6K]

1. A model of a famous statue is 2\dfrac{1}{2} inches tall that is

\dfrac{2\cdot 2+1}{2}=\dfrac{5}{2} in.

2. The actual statue is 3\dfrac{1}{3} feet tall that is

\dfrac{3\cdot 3+1}{3}=\dfrac{10}{3}\ ft=\dfrac{10}{3}\cdot 12=40\ in.

3. The ratio of the height of the model to the height of the actual statue in simplest form is

\dfrac{\dfrac{5}{2}}{40}=\dfrac{5}{2}\cdot \dfrac{1}{40}=\dfrac{1}{16}.

Answer: \dfrac{1}{16}.

4 0
3 years ago
The coefficient of x in -7xy is -7​
Oksanka [162]

Answer:

True: the leading coefficient in the monomial is -7

Step-by-step explanation:

Math

5 0
2 years ago
In the figure, AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. Prove that △AEB ≅ △DEC
Makovka662 [10]

Answer:

From top to bottom:

A, J, E, B, I, C, D, G, F, H

See below for more clarification.

Step-by-step explanation:

We are given that AB is parallel to CD, XY is the perpendicular bisector of AB, and E is the midpoint of XY. And we want to prove that ΔAEB ≅ ΔDEC.

Statements:

1) XY is perpendicular to AB.

Definition of perpendicular bisector.

2) XY ⊥ CD.

In a plane, if a transveral is perpendicular to one of the two parallel lines, then it is perpendicular to the other.

3) m∠AXE = 90°, m∠DYE = 90°.

Definition of perpendicular lines.

4) ∠AXE ≅ ∠DYE.

Right angles are congruent.

5) XE ≅ YE

Definition of a midpoint.

6) ∠A ≅ ∠D.

Alternate Interior Angles Theorem

7) ΔAEX ≅ ΔDEY

AAS Triangle Congruence*

(*∠A ≅ ∠D, ∠AXE ≅ ∠DYE, and XE ≅ YE)

8) AE ≅ DE

Corresponding parts of congruent triangles are congruent (CPCTC).

9) ∠AEB ≅ ∠DEC

Vertical Angles Theorem

10) ΔAEB ≅ ΔDEC

ASA Triangle Congruence**

(**∠A ≅ ∠D, AE ≅ DE, and ∠AEB ≅ ∠DEC)

3 0
3 years ago
Find the 16th term , given the first term and the common difference. a1=8 and d=3
sattari [20]
By using the formula for arithmetic sequence, the 16th term of the progression can be obtained. Given A1=8 and d=3,
A16=A1+(n-1)d
A16=8+(16-1)(3)
A16=53
8 0
3 years ago
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