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Thepotemich [5.8K]
2 years ago
10

class="latex-formula">

\tt Thanks! :)
Mathematics
2 answers:
Rzqust [24]2 years ago
8 0
X = -3

Solution:
Distribute
6(x)+(6)(-1)+-x=-21

Combine
(6x+-x) + (-6) = -21
5x + -6 = -21
5x - 6 = -21

Add 6 to both sides
5x -6 + 6 = -21 +6
5x = -15

Divide both sides by 5
5x/5 = -15/5
x = -3
zalisa [80]2 years ago
4 0

Step-by-step explanation:

Given that:

6(x - 1) - x = -21

Multiply the number outside of the brackets with numbers in the brackets on LHS.

⇛6x - 6 - x = -21

Shift constant from LHS to RHS, changing it's sign.

⇛6x - x = -21 + 6

Subtract the values on LHS and RHS.

⇛5x = -15

Shift the number 5 from LHS to RHS.

⇛x = -15/5

Therefore x = -3

Please let me know if you have any other questions.

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In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

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Answer:

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Which Expression can be used to solve 3/5÷7/10A. 5/3*7/10B. 5/3*10/7C. 3/5*10/7D. 3/5*7/10
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Which Expression can be used to solve 3/5÷7/10



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