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ale4655 [162]
3 years ago
8

MATH AID PLEASE HELP?

Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

The area of a trapezoid is

\cfrac{(B+b)h}{2}

where B and b are the two bases, and h is the height. The two bases have to be parallel, and the height must be perpendicular to both bases.

Even though we are used to have horizontal bases and vertical height, it's not mandatory, since a simple rotation doesn't affect the dimensions or the area of the trapezoid.

So, in this case, the two vertical segments are actually the bases of the trapezoid, and the horizontal segment is the height. So, the formula for the area yields

A = \cfrac{(12.2+10.2)\cdot 12.6}{2} = \cfrac{22.4\cdot 12.6}{2} = 11.2\cdot 12.6 = 141.12

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HELP ASAp!!! Will give brainlest. Find all solutions of the equation in the interval
love history [14]

Answer:

7/6π, 1/6π

Step-by-step explanation:

We know that tan is sine/cosine, so cot is cosine/sine.

In this case, we know cotθ = √3

As the number is positive, using the unit circle, we now can say that the two solutions are in quadrants I and III.

Taking a look at the unit circle, we can finalize our answer.

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2 years ago
What is the probability of landing on heads when flipping a fair coin?
olga2289 [7]

Answer:

1/2

Step-by-step explanation:

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3 years ago
Read 2 more answers
write the x and y coordinate (in the second and third column, respectively) of dilation of quadrilateral ABCD with vertices A(1,
gayaneshka [121]

Answer:

The coordinates of the dillated vertices are A'(x,y) = (2,2), B'(x,y) = (4,4), C'(x,y) = (8,2) and D'(x,y) = (4,-2).

Step-by-step explanation:

From Linear Algebra, we define dilation by the following equation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

Where:

O(x,y) - Center of dilation, dimensionless.

P(x,y) - Original point, dimensionless.

k - Scale factor, dimensionless.

P'(x,y) - Dilated point, dimensionless.

If we know that O(x,y) = (0, 0), k = 2, A(x,y) = (1,1), B(x,y) = (2,2), C(x,y) = (4,1) and D(x,y) = (2,-1), then the dilated points are, respectively:

Point A

A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)] (2)

A'(x,y) = (0,0) + 2\cdot [(1,1)-(0,0)]

A'(x,y) = (2,2)

Point B

B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)] (3)

B'(x,y) = (0,0) + 2\cdot [(2,2)-(0,0)]

B'(x,y) = (4,4)

Point C

C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)]

C'(x,y) = (0,0) + 2\cdot [(4,1)-(0,0)]

C'(x,y) = (8,2)

Point D

D'(x,y) = O(x,y) + k\cdot [D(x,y)-O(x,y)]

D'(x,y) = (0,0) + 2\cdot [(2,-1)-(0,0)]

D'(x,y) = (4,-2)

The coordinates of the dillated vertices are A'(x,y) = (2,2), B'(x,y) = (4,4), C'(x,y) = (8,2) and D'(x,y) = (4,-2).

4 0
3 years ago
Solve the triangle. Round your answers to the nearest tenth.
Tresset [83]

Answer:

<B = 47°

<C = 28°

b = AC = 28.0

Step-by-step explanation:

Given:

∆ABC

AB = c = 18

BC = a = 37

<A = 105°

Required:

Length of AC = b

measure of angle B and angle C

SOLUTION:

==>Use the sine rule, sin A/a = sinC/c to find the angle of C:

SinA = sin(105) = 0.9659

a = 37

sinC = ?

c = 18

0.9659/37 = sinC/18

Cross multiply

0.9659*18 = 37*sinC

17.3862 = 37*sinC

Divide both sides by 37

17.3862/37 = sinC

0.4699 = sinC

sinC = 0.4699

C = Sin-¹(0.4699)

C = 28.0° (nearest tenth)

==>Find angle B using sum of angles in a triangle:

Angle B = 180 - (105+28)

Angle B = 180 - 133

Angle B = 47°

==>Find length of b using sine rule, b/sinB = c/sinC:

SinC = sin(28) = 0.4695

SinB = sin(47) = 0.7314

c = 18

b = ?

b/0.7314 = 18/0.4695

Cross multiply

b*0.4695 = 18*0.7314

b*0.4695 = 13.1652

Divide both sides by 0.4695

b = 13.1652/0.4695

b = 28.0 (nearest tenth)

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3 years ago
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dimulka [17.4K]

Answer:

0.667 or 0.666 (with the line over the last sixth)

Step-by-step explanation:

The original answer is 0.666666666666666 (continued on forever). Find the third decimal place and determine whether the next number follows the "5 or greater" rounding rule and round from there. The answer depends on the type of teacher.

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