From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.
Using pythagoras theorem,

and

Angle θ is given by

Given that a = 4 units, b = 5 units, and c = 9 units, thus

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.

Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
F hope that helped have anger he try’s
10(6) + 25 = 60 + 25 = 85
10(2.75) + 25 = 27.5 + 25 = 52.5
10(1.482) + 25 = 14.82 + 25 = 39.82
93 = 10x + 25 || 68 = 10x || x = 6.8
42.1 = 10x + 25 || 17.1 = 10x || x = 1.71
116.25 = 10x + 25 || 91.25 = 10x || x = 9.125
Answer is x is less than 4