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Delicious77 [7]
3 years ago
5

6.5 subtract decimal 4.08-1.74

Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0
Are `you asking whats 4.08-1.74? its 2.34
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Give the required elements of the hyperbola.
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b

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Write the expression in simplest form using only positive exponents (x^2/3y^-1/2)^-6
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\left( \cfrac{x^2}{3y^{- \frac{1}{2} }} \right)^{-6}=\left( \cfrac{3y^{- \frac{1}{2} }}{x^2} \right)^{6}=\left( \cfrac{3}{x^2y^{ \frac{1}{2} }} \right)^{6}= \cfrac{3^6}{x^{2*6}y^{ \frac{1}{2}*6 }} = \cfrac{729}{x^{12}y^3}
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3 years ago
According to a​ survey, 65​% of murders committed last year were cleared by arrest or exceptional means. Fifty murders committed
monitta

Answer:

a) P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421

b) P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714

P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502

P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319

And adding these values we got:

P(36 \leq X \leq 38)= 0.1535

c) We can find the expected value given by:

E(X) = np =50*0.65 = 32.5

And the standard deviation would be:

\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

\mu -2\sigma = 32.5- 2*3.373 = 25.75

And then we can consider a value of 18 as unusual lower for this case.

Step-by-step explanation:

Let X the random variable of interest "number cleared by arrest or exceptional", on this case we can model this variable with this distribution:

X \sim Binom(n=50, p=0.65)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

We want this probability:

P(X=41)=(50C41)(0.65)^{41} (1-0.65)^{50-41}=0.00421

Part b

We want this probability:

P(36 \leq X \leq 38)

We can find the individual probabilities:

P(X=36)=(50C36)(0.65)^{36} (1-0.65)^{50-36}=0.0714

P(X=37)=(50C37)(0.65)^{37} (1-0.65)^{50-37}=0.0502

P(X=38)=(50C38)(0.65)^{38} (1-0.65)^{50-38}=0.0319

And adding these values we got:

P(36 \leq X \leq 38)= 0.1535

Part c

We can find the expected value given by:

E(X) = np =50*0.65 = 32.5

And the standard deviation would be:

\sigma = \sqrt{np(1-p)} \sqrt{50*0.65*(1-0.65)}= 3.373

We can use the approximation to the normal distribution and we have at leat 95% of the data within 2 deviations from the mean. And the lower limit for this case would be:

\mu -2\sigma = 32.5- 2*3.373 = 25.75

And then we can consider a value of 18 as unusual lower for this case.

6 0
3 years ago
Which shows two expressions that are equivalent to (Negative 7) (Negative 15) (Negative 5) Yan is climbing down a ladder. Each t
Svet_ta [14]

Answer:

(-8) + (-8) + (-8) + (-8)

Step-by-step explanation:

Since Yan is descending ; we represent his movement as being negative.

Number of rungs descended before stopping = 4

Number of stops = 8

Given that no extra steps was taken ;

Number of ladder rungs descended :

4 rungs per stop for 8 stops

- 4 * 8 = - 32 rungs

Another way to write the product :

Number of stops added in number of rungs descended :

(-8) + (-8) + (-8) + (-8)

3 0
2 years ago
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