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kakasveta [241]
3 years ago
12

Write the expression in simplest form using only positive exponents (x^2/3y^-1/2)^-6

Mathematics
1 answer:
hoa [83]3 years ago
5 0
\left( \cfrac{x^2}{3y^{- \frac{1}{2} }} \right)^{-6}=\left( \cfrac{3y^{- \frac{1}{2} }}{x^2} \right)^{6}=\left( \cfrac{3}{x^2y^{ \frac{1}{2} }} \right)^{6}= \cfrac{3^6}{x^{2*6}y^{ \frac{1}{2}*6 }} = \cfrac{729}{x^{12}y^3}
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so 2 large pies out of eight pies
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7. Which is the area of a rectangle TYOC with vertices T(-6, 6), Y(2, 10), 0(4, 6),
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3 years ago
For A I somehow got 41.05 but its 2.95cm can someone show me the working and what I did wrong?
777dan777 [17]

Answer:

Step-by-step explanation:

a). tan(75°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

                  = \frac{11}{k}

    k = \frac{11}{\text{tan}(75)}

    k = 2.947

    k = 2.95 cm

b). cos(52°) = \frac{16}{s}

    s = \frac{16}{\text{cos}(52)}

    s = 25.988

    s ≈ 25.99 cm

c). sin(5°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

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    q = \frac{16.1}{\text{sin}(5)}

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4 0
3 years ago
What’s the area<br> A. 64<br> B. 44<br> C. 30.25<br> D. 13.75
dalvyx [7]

Answer:

B) 44

Step-by-step explanation:

Let's start with the triangles. Normally, when dealing with triangles, you would use the formula (B*H*1/2), but since there's two identical triangles, we can just do (B*H) and get the area for both:

2.5*5.5=<u>13.75</u>

Then to solve for the square, it is also (B*H):

5.5*5.5=<u>30.25</u>

At this point, to solve for the total area, you just add the areas together:

13.75+30.25=<u>44</u>

<u />

Hope this helps!

6 0
3 years ago
Read 2 more answers
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