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3 years ago

A $6000 investment earns $690 simple interest in two years. What is the annual interest rate?

1 answer:

6 0

2 years simple interest is $690
1 year simple interest is $690/2 = $345

$6000 simple interest is $345
$1000 simple interest is $345/6 = $57.5
$100 simple interest is $57.5/10 = $5.75

Annual interest rate is 5.75%

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The perimeter of the triangle at the right is 22.6 in. What is the value of n?

blagie [28]

Answer:

A. 3.5

Step-by-step explanation:

The perimeter is just the sum of all of the side lengths. The sides of this triangle are n inches, (n + 5.2) inches, and (2n + 3.4) inches.

So, your equation is n + n + 5.2 + 2n + 3.4 = 22.6 inches.

You can combine like terms (adding together all of the n's and all of the numbers) to simplify your equation to 4n + 8.6 = 22.6 inches.

Subtract 8.6 from both sides of the equation to get 4n = 14, and divide both sides by 4 to get n = 3.5.

Hope this helps! :)

8 0

2 years ago

Find the y-coordinate of the y-intercept of the polynomial function defined below.

gayaneshka [121]

The y-intercept would be (0,8) because the last number on the equation, aka the c value, is you y-intercept.

5 0

3 years ago

What is the solution for 2y=x+2 x-3y=-5

Mars2501 [29]

Answer:

x = 4

y = 3

Step-by-step explanation:

Given equations :-

2y = x + 2
x - 3y = -5

Second equation can be written as ,

x - 3y = -5
-3y = -x - 5

Adding them :-

-3y + 2y = 2 -5
-y = -3
y = 3

Put this in (ii) :-

x = 3y - 5
x = 3*3 - 5
x = 9 -5
X = 4

8 0

3 years ago

Read 2 more answers

A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro

Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let $\mu$ be the true mean weight per apple the company ship. We want to test the next hypothesis

$H_{0}:\mu=120$ vs $H_{1}:\mu\neq 120$ (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

$Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}}$ which is normally distributed. The observed value is

$z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583$ . The rejection region for $\alpha = 0.05$ is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0

3 years ago

Help brainliest if all’ answers are correct if not report answer all’ questions plz (10 points)

Naya [18.7K]

2. 11 2/16 that’s for answers number 2

3 0

3 years ago