Answer:
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by
where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
reduce fraction:
By using calculator we acquire:
hence, the remaining sample after 420 days is 0.625 kg
120 + 0.40m = 50 + 0.50m
120 - 50 = 0.50m - 0.40m
70 = 0.10m
70/0.10 = m
700 = m....they will be the same at 700 miles
Your answer is correct it’s 4/33. You first have to convert the mixed number into an improper fraction. Then you’ll have 1/6/11/8 and then you will simplify the complex fraction. I hope that helps!
Answer:
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Step-by-step explanation:
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Answer:1.09090909091
Step-by-step explanation: