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MariettaO [177]

4 years ago

9

An individual is planning a trip to a baseball game for 20 people. Of the people planning to go to the baseball game, 11 can go

on Saturday and 14 can go on Sunday, some of them can go on both days. How many people can only go to the game on Saturday?

1 answer:

storchak [24]4 years ago

4 0

Answer:

6 people

Step-by-step explanation:

Suppose A represents the event of going on Saturday,

B represents the event of going on Sunday,

According to the question,

n(A)=11

n(B)=14

n(A∪B)=20

We know that,

n(A∪B) = n(A) + n(B) - n(A∩B)

By substituting values,

20 = 11 + 14 - n(A∩B)

⇒ n(A∩B) = 25 - 20 = 5,

Hence, the number of people who can only go to the game on Saturday = n(A) - n(A∩B) = 11 - 5 = 6.

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b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

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Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

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On the otherhand; let the radius (r) of the circle be;

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Area of the circle which is πr² can now be;

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Total Area (A);

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If we divide through with (2) and each entity move to the opposite side; we have:

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By cross multiplying; we have:

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collect like terms

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= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

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The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

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