Bruh
so toal cost=28 right?
total cost=total cost of water+total cost of tickets
water=3
subsitute 28=total cost and 3=total cost of water
28=3+total cost of tickets
remember we can do anything to an equaton as long as you do it to both sides
28=3+total cost of tickets
subtract 3 from both sides
28-3=3-3+total cost of tickets
25=0+cost of tickets
25=cost of tickets
if he bought 5 tickets, how much does each cost
25=5tickets
divide both sides by 5
25/5=5/5tickets
5=1tickets
answer is 1 ticket cost $5.00
equation is
total cost=water+tickets
28=3+5tickets
Step-by-step explanation:
soln:
let,
(x1,y1) =(2,4)
(x2,y2)=2,-7)
Now,
By midpoint formula,
×= <u>x</u><u>1</u><u>+</u><u>x</u><u>2</u>
2
= <u>2</u><u>+</u><u>2</u>
2
=<u>4</u>
2
=2,,
And,
Y=<u>y</u><u>1</u><u>+</u><u>y</u><u>2</u>
2
=<u>4</u><u>-</u><u>7</u>
2
= <u>-</u><u>3</u>
2
Hence ,
The mispoint between points (2,4) and (2,-7) is (2,<u>-</u><u>3</u><u> </u><u> </u><u> </u><u>)</u>
2
This should be commutative
To approximate the number of chairs that can be set up in floor space, we just have to divide the total floor area by the area that each chair needs. That is,
n = (40 ft x 32 ft) / (4 ft x 5 ft)
n = 64
Therefore, there are 64 chairs that can be set up in the floor.
X+y=20
xy=99
Let a+b be denoted a,b
20 = 1,19 2,18 3,17 4,16 5,15, 6,14 7,13 8,12 (9,11) ..Stop
99=3^2*11
Thus the ages are 11 and 9 with a difference of 2.