Answer:
for 9, the answer is 246.49
Step-by-step explanation:
This is area of a circle correct?
The formula is PI x radius squared.
3.14 x the radius, which is 5, squared
I am re-editing this
so sorry the answer is actually 78.54
The reason why it is 78.54 is that you need to square the radius before multiplying with PI.
Here's an explanation! :)
The student with the correct answer is Dylan who says the decimal should be placed between the 8 and 0.
This is base on the estimation that 3.01 is a two decimal place number, so the product 18.06 should also be in 2 decimal place.
<h3>How to find product of decimal number?</h3>
A decimal number is a number expressed in the decimal system (base 10).
Place value:
- Ten thousand
- Thousand
- Hundred
- Ten
- ones
- . decimal point
- tenth
- hundredths
- thousandth
- ten thousandth
- hundred thousandth
6 × 3.01
3.01
- 3 = ones
- . = decimal point
- 0 = tenth
- 1 = hundredth
6 × 3.01
= 18.06
Therefore, Lucas is incorrect with his answer that the decimal should be placed between the 1 and 8.
Read more on decimal number:
brainly.com/question/1827193
#SPJ1
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:

And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221