A number halved and then halved again is equal to 2 what was the original number
1 answer:
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Hi there!
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I believe your answer is:
(-3, -1) and (1, 3)
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Here’s why:
- I have graphed the two equations given on a graphing program.
- When graphed, they pass at points (-3, -1) and (1,3). Therefore, they are the solutions to the system.
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See the graph attached.
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Hope this helps you. I apologize if it’s incorrect.
So you want to solve for x?
It would be nice if this would easily factor:
(-4x + 5)(2x +1) = 0 This will not work!
So you need to use the quadratic formula:
a = -8, b = 4, c = 5
x = (-4 +/-
)/2(-8)
= (-4 +/-
)/-16
= (-4 +
)/-16
= 1/4 -
/4
It would be nice if this would easily factor:
(-4x + 5)(2x +1) = 0 This will not work!
So you need to use the quadratic formula:
a = -8, b = 4, c = 5
x = (-4 +/-
= (-4 +/-
= (-4 +
= 1/4 -