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Scilla [17]
3 years ago
15

Sorry I didn’t post Wednesday so I will post Wednesday and Thursday Answer the question

Mathematics
2 answers:
Leona [35]3 years ago
7 0

An internet company charges $57 for 6 months.

Solution:

Given data:

Internet company charge per month = $9.50

Charge for number of months = 6

<u><em>To find the charge of amount for 6 months:</em></u>

Charge for 6 months = 9.50 × 6

                                   = 57

Charge for 6 months = $57

That is $57 for this service.

Hence an internet company charges $57 for 6 months.

grin007 [14]3 years ago
4 0

1. The options B and C are true.

2. The service will cost $57.00 for 6 months.

Step-by-step explanation:

Step 1; First, we must convert all the fractions into decimals by dividing the values. The values are as follows

\frac{4}{8} = 0.5, \frac{3}{6} = 0.5, \frac{6}{6} = 1, \frac{4}{5} = 0.8, \frac{7}{8} = 0.875, \frac{5}{6} = 0.833, \frac{3}{8} = 0.375, \frac{4}{10} = 0.4,                 \frac{2}{3} = 0.666, and \frac{4}{5} = 0.8.

Step 2; Now we compare the values.

Option A; 0.5 < 0.5, this is incorrect as the values are equal.

Option B; 1 > 0.8, this is true.

Option C; 0.875 > 0.833, this is also true.

Option D; 0.375 > 0.4, this is incorrect as 0.4 is greater than 0.375.

Option E; 0.666 > 0.8, this is also incorrect as 0.8 is the greater value

Step 3; The service costs $9.50 a month so for 6 months it will cost                 6 × $9.50 = $57.00.

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Drina wrote the system of linear equations below.
zalisa [80]

Answer:

Option c, A square matrix

Step-by-step explanation:

Given system of linear equations are

3x-2y=-2\hfill(1)

7x+3y=26\hfill(2)

-x-11y=46\hfill(3)

Now to find the type of matrix can be formed by using this system

of equations

From the given system of linear equations we can form a matrix

Let A be a matrix

A matrix can be written by

A=co-efficient of x of 1st linear equation    co-efficient of y of 1st linear equation   constant of 1st terms linear equation

co-efficient of x of 2st linear equation   co-efficient of y of 2st linear equation  constant of 2st terms linear equation

co-efficient of x of 3st linear equation   co-efficient of y of 3st linear equation    constant of 3st terms linear equation           3\times 3

which is a 3\times 3 matrix.

Therefore A can be written as

A= \left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3

Matrix "A" is a 3\times3 matrix so that it has 3 rows and 3 columns

A square matrix has equal rows and equal columns

Since matrix "A" has equal rows and columns Therefore it must be a square matrix

Therefore the given system of linear equation forms a square matrix

7 0
3 years ago
Read 2 more answers
Help help help help |0.75−0.25z |= 3/4
Arada [10]
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3 0
3 years ago
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Find the Area of this figure.
grin007 [14]

Answer:

158 m²

Step-by-step explanation:

I made this into 3 rectangles.

Figure 1:

9•8=72

The 9 is from the 13 m side, but I've taken 4 m off from the overlapping square.

Figure 2:

6•7=42

The 7 is from the 10 m side, but I've taken 4m off from the overlapping square again.

Remaining Area:

If you extend the lines into figures 1 and 2 from the top left corner and bottom right corner vertically, you will get a rectangle that is (11 m) x (4 m). This is not yet accounted for.

11•4=44

Add together: 72 + 42 + 44 = <u>158</u>

*Note: You could also find the area of the squares a much easier way by subtracting the overlapping part after finding the area of both figures , but this is how I did it*

5 0
3 years ago
Christy dove to a depth of 12 feet below the surface of the water. Write the depth as an integer
puteri [66]
-12 because surface is usually considered as "0" so 12 ft below the surface means -12.
6 0
3 years ago
Determine the rate of change of the following linear equation as it translates from (-5, -1) to any other point on the line.
anzhelika [568]

The rate of change of the linear equation is -\frac{2}{3}

Explanation:

The given two coordinates are (-5,-1) and (1,-5)

To determine the rate of change, let us use the formula,

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Substituting the coordinates in the equation, we get,

m=\frac{-5+1}{1+5}

Simplifying, we have,

m=\frac{-4}{6}

Dividing, we get,

m=-\frac{2}{3}

Thus, the rate of change of the linear equation is -\frac{2}{3}

7 0
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