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Artyom0805 [142]
3 years ago
13

Which is the solution to the equation solved for p? (q + p)q = (s + r)s

Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

Option B

Step-by-step explanation:

(q + p)q = (s + r)s

Lets open the brackets of L.H.S.

=> q^2 + pq = (s+ r)s

Lets substract q² from both the sides.

=> q^2 + pq - q^2 = (s + r)s - q^2

=> pq = (s + r)s - q^2

Lets divide both the sides by q.

=> \frac{pq}{q} = \frac{(s + r)s - q^2}{q}

=> p = \frac{(s + r)s }{q} - \frac{q^2}{q} = \frac{(s + r)s}{q} - q

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3 years ago
It is not a function because both (2, 2) and (2,−2) have the same x-coordinate. It is a function because both (2, 2) and (2,−2)
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