Answer:
19 cows and 3 chickens
18 cows and 5 chickens
17 cows and 7 chickens
16 cows and 9 chickens
15 cows and 11 chickens
Step-by-step explanation:
For example, the first one
19 cows x 4 legs=76 legs and
3 chickens x 2 legs= 6 legs
3 seconds
0= -16t^2+144
-144/-16=9
9=t^2
Sq rt of 9 is 3
Hello!
Here's how much each person stacked:
Ronnie -- 0.25 of the 40 pizzas.
Mack -- 9/40
Kim -- 35% of the 40 pizzas.
Ada -- rest of the pizzas.
Now, the questions asks for who stacked the most pizzas.
First, find our how many pizzas they stacked out of 40.
40 × 0.25 = 10
40 × 35% = 14
10 + 9 + 14 = 33
40 - 33 = 7
This means that Ronnie stacked 10 pizzas, Mack stacked 9 pizzas, Kim stacked 14 pizzas, and Ada stacked 7 pizzas.
ANSWER:
Kim stacked the most pizzas since she stacked 14 of them.
Answer:
The least number of tennis balls needed for the sample is 1849.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population proportion is:

The margin of error for this interval is:

Assume that the proportion of all defective tennis balls is <em>p</em> = 0.50.
The information provided is:
MOE = 0.03
Confidence level = 99%
<em>α</em> = 1%
Compute the critical value of <em>z</em> for <em>α</em> = 1% as follows:

*Use a <em>z</em>-table.
Compute the sample size required as follows:

![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%20%7D%7BMOE%7D%5D%5E%7B2%7D)
Thus, the least number of tennis balls needed for the sample is 1849.