Which statement is not used to prove that triangle ABC is similar to triangle ADC?

Mathematics

1 answer:

yarga [219]2 years ago

6 0

Answer:

what are the statements we pick from?

Step-by-step explanation:

most likely look out for angles and lengths that go against the established ratio

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Need help checking if they are right

Stells [14]

Answer:

Step-by-step explanation:

so I see at the top , it's saying the triangles are "similar" this is a very important part. meaning that the triangles are copies of each other just bigger or smaller but other wise the same.

QR is 25 check

HG is 30 check

X1 = 48 check

X2 = 14 check

x3 = 6 check

7 0

3 years ago

Read 2 more answers

The gravitational force formula is F=Gm1m2 where F is the force between two objects, G is the constant of gravitation, m1 is the

Kruka [31]

$\text{r = }\dfrac{\sqrt{G*m_1*m_2}}{\sqrt{F}}$

This is what is in the middle of the second paragraph. That statement is correct.

I don't know that it is any simpler or not, but what they have done in the answer is rationalize the denominator. That means that the denominator is no longer under the square root sign.

To get that result, you multiply numerator and denominator by √F

When you do that, your get

$\text{r =}\dfrac{G\sqrt{m_1*m_2}\sqrt{F}} { \sqrt{F*}\sqrt{ F}}$

This results in the middle answer.

$\text{r = } \dfrac{ \sqrt{G m_1*m_2*F}}{F}$

6 0

3 years ago

Read 2 more answers

Find the value of cos θ if the angle θ is in the third quadrant and sinθ= -0.8

Rudiy27

Correct option is D) -0.6.

<u>Step-by-step explanation:</u>

We have $sin\alpha = -0.8$ . Also, we know that $cos\alpha = \sqrt{1- (sin\alpha } )^{2}$ . Let's find out value of $cos\alpha$ using above formula: