The answer for H is, s=nb+nh÷3
Hope it helps
Perimeter: P=24 ft
Lenght: L
Width: W
The length is 2 ft longer than the width:
(1) L= W+2 ft
Perimeter: P=2(W+L)
P=24 ft
2(W+L)=24 ft
Dividing both sides of the equation by 2:
2(W+L)/2 =(24 ft)/2
(2) W+L=12 ft
We have a system of 2 equations and 2 unkowns:
(1) L=W+2
(2) W+L=12
Using the method of substitution: Replacing L by W+2 in the second equation:
(2) W+L=12
W+(W+2)=12
W+W+2=12
2W+2=12
Solving foe W
2W+2-2=12-2
2W=10
Dividing both sides of the equation by 2:
2W/2=10/2
W=5
Replacing W by 5 in the first equation:
(1) L=W+2
L=5+2
L=7
Answers:
What is the width? 5 ft
What is the length? 7 ft
Answer:
9*572=5148
Step-by-step explanation:
Answer:
k = 2a = 10
Step-by-step explanation:
If
x² / 25 − y² / 56 = 1
we know that
a² = 25 ⇒ a = 5
b² = 256 ⇒ b = √256
The equation of the hyperbola defined by |FP − PG| = k can be written as follows:
|FP − PG| = 2*a
then
2*a = 2*5 = 10
