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3 years ago

8

Meg trade Australian dollars for Mexican pesos at an exchange rate of one AU for 13 For Mexican pesos She gave exchanger a total

of 1800 Australian dollars and was charged a flat fee of AU$65 Approximately how many Mexican pesos did Johnny get

1 answer:

VashaNatasha [74]3 years ago

6 0

Answer:

22,555

Step-by-step explanation:

1,800 - 65 = 1,735

1,735 x 13 = 22,555

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Step-by-step explanation:

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Komok [63]

correct answer is option d.

<u>Step-by-step explanation:</u>

Here, we have The following expression to check Which of the following is a polynomial with roots: −square root of 3 , square root of 3, and 2 :

<u>a. x3 + 3x2 − 5x − 15 </u>

For $-\sqrt{3}$ , $x^{3} + 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3} + 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

<u>b. x3 + 2x2 − 3x − 6 </u>

For $-\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(-\sqrt{3}) ^{3} + 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) -6$ = 0 .

For $\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(\sqrt{3}) ^{3} + 2(\sqrt{3} )^{2} -3(\sqrt{3} ) -6$ = 0.

For 2 , $x^{3} + 2x^{2} -3x -6$ ⇒ $(2) ^{3} + 2(2)^{2} -3(2 ) -6$ $\neq 0$ . So, this isn't the one. We move on further!

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<u>d. x3 − 2x2 − 3x + 6</u>

For $-\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(-\sqrt{3}) ^{3} - 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) +6$ = 0 .

For $\sqrt{3}$ , $x^{3} - 2x^{2} -3x +6$ ⇒ $(\sqrt{3}) ^{3} -2(\sqrt{3} )^{2} -3(\sqrt{3} ) +6$ = 0.

For 2 , $x^{3} - 2x^{2} -3x +6$ ⇒ $(2) ^{3} - 2(2)^{2} -3(2 ) +6$ = 0.

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3 years ago

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e-lub [12.9K]

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butalik [34]

Answer:

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Step-by-step explanation:

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