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julsineya [31]
3 years ago
15

Suppose that b(t)b(t) measures the number of bacteria living in a colony in a petri dish, where bb is measured in thousands and

tt is measured in days. one day, you measure that there are 6,000 bacteria and the per capita growth rate is 3.
Biology
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

To begin your question is incomplete, since it would be missing as many days as you want to pass to reach a certain number of bacteria ...

But I can explain to you that with what you put if you have the complete question in your notebook:

Bacteria are usually grown in petri dishes, which are glass capsules where you generate a perfect medium (culture) with all the necessary nutrients for them to live, grow and reproduce ... The bacteria we are talking about in this problem says that reproduce with an exponential of 3, this means that if there are 6000 bacteria today, we multiply that value by 3 and we already know how many there will be tomorrow (3x6,000 = 18,000), if we continue with the same analysis, the day after tomorrow there will be many more ... why? Because the account you would have to do is tomorrow's value multiplied by 3, that is, 18,000x3 = 54,000 !!!

Explanation:

It is important to know that growth with exponent 3 will always generate that the bacterial multiplication of each day is by 3, on the other hand, this serves to understand the magnitude with which bacteria populations grow, and with the rapidity that they do. .

So as a summary we would have to:

today you have 6,000 bacteria

tomorrow 18,000 bacteria (6,000x3)

the day after tomorrow 54,000 bacteria (18,000x3) ...

In just 3 days the bacteria reached a number of 54,000, now look in your folder what number of days your teacher asked you and continue with the account!

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How do organisms interact with the living and  non-living elements of their environments?

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Mantle plumes are areas of hot, upwelling mantle and hot spots develops above these plumes as noted in the map above. Magma gene
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3 years ago
Humans and baboon have noses with nostrils that face downward, but many other primates have noses with nostrils that face out to
Zepler [3.9K]

Answer:

a shared derived trait.

Explanation:

Genetics can be defined as the scientific study of hereditary in living organisms such as humans, animals and plants.

Simply stated, a trait refers to the specific features or characteristics possessed by a living organism. It is essentially transferred from the parent of a living organism to her offspring and as such distinguishes him or her.

Heredity refers to the transfer of traits (specific characteristics) from the parent of a living organism to her offspring through sexual reproduction or asexual production. Some examples of hereditary traits are dimples, tongue rolling, baldness, weight, handedness, freckles, curly hair, hair color, blindness, complexion, height, etc.

All humans and baboons are created having noses with nostrils underneath i.e facing downwards but other primates such as platyrrhines have their nostrils facing sideways (face out to the side). Also, humans and baboons shared close similarities with each other when compared than they share with the primates having a outward-facing nostrils.

This ultimately implies that, both humans and baboons sharing the downward-facing nostril orientation is an example of a shared derived trait.

A shared derived trait can be defined as a trait or characteristic that is shared between two lineages and subsequently evolves leading up to a clade, which is a distinguishing feature from other species.

4 0
2 years ago
You discover a population of mustard plants and find it to be at Hardy–Weinberg equilibrium with respect to the R locus. Suppose
natulia [17]

Answer:

The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.

Explanation:

According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:

p + q = 1

r-6 + R = 1  

0.2 + 0.8 = 1

Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64

The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04

And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32

5 0
3 years ago
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