Question

Solve logs (8 - 3x) = log20 for x. A. X = 14 B. X = -13 C.x = -8 D. X= -4

Answer 1

Answer:

$\boxed{\sf x = -4}$

Step-by-step explanation:

$\sf Solve \: for \: x \: over \: the \: r eal \: numbers:$

$\sf \implies log(8 - 3x) = log 20$

$\sf Cancel \: logarithms \: by \: taking \: exp \: of \: both \: sides:$

$\sf \implies 8 - 3x = 20$

$\sf Subtract \: 8 \: from \: both \: sides:$

$\sf \implies 8 - 3x - 8 = 20 - 8$

$\sf \implies - 3x = 12$

$\sf Divide \: both \: sides \: by \: - 3:$

$\sf \implies \frac{-3x}{-3} = \frac{12}{-3}$

$\sf \implies x = - 4$

Answer 2

Answer:

x = -4

Step-by-step explanation:

logs (8 - 3x) = log20

Since we are taking the log on each side

log a = log b  then a = b

8 -3x = 20

Subtract 8  from each side

8 -3x-8 =20 -8

-3x = 12

Divide by -3

-3x/-3 = 12/-3

x = -4