This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
Answer:
16/13
Step-by-step explanation:
Use a calculator lol
Can I have brainliest please
"Joint variation<span>" means "directly, but with two or more variables". Thus, we write as follows:
j </span>α gv
<span>
We insert proportionality constant k, to change it to equality.
j = kgv
We solve k,
1 = k (4)(3)
k =1/12
j = gv/12
j = 8(11)/12
j = 22/3</span>
Ok so first you should suck ur m0ms d1ck
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