I need help with this problemwill mark as brainliest
1 answer:
Answer:
The shop can cut the cost of production per sandwich to $3.75. The revenue function would then be defined as R(x)=9x.
Step-by-step explanation:
We want to make as big profit as possible by making as little sandwiches as possible. This means that we want the profit, which is to be as big as possible.
For the first choice the profit per sandwich is dollars.
For the second choice the profit per sandwich is dollars.
For the third choice the profit per sandwich is dollars.
We see here that for the second choice the profit is greatest, therefore this choice is most suitably correct.
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Answer:
1)4
2)28
3)18.3
4)38.5
5)22.5
6)19.25
7)25.5
8)69.666
9)6.5
10)22.666
Step-by-step explanation:
- To do this first you should convert the mix numbers into inproper fractions and then solve.
1)8/5*5/2=4
2)21/5*20/3=7*4
=28
3)33/4*20/9=11*5/3
=55/3
=18.33...
=18.3
4)35/6*33/5=7*11/2
=77/2
=38.5
5)22/8*90/11=45/2
=22.5
6)11/3*21/4=11*7/4
=77/4
=19.25
7)34/5*15/4=34*3/4
=25.5
8)22/3*57/6=11*19/3
=209/3
=69.666
9)39/8*4/3=13/2
=6.5
10)17/2*8/3=17*4/3
=68/3
=22.666
<em>Hope you got this</em>
<em>If you have any doubt please ask me</em>
<em>If you need this in fraction form just check the attachment</em>
Answer:
2.20752 x
Step-by-step explanation:
The first thing you have to do is to look for the number of seconds in one year. You have to multiply 365 days by 86,400 seconds.
- 365 days refer to the total number of days per year
- 86,400 seconds refer to the number of seconds per day
Let's solve.
- 365 x 86,400 = 31,536,000 or 3.1536 x
<em>Therefore, one year has 3.1536 x </em><em> seconds.</em>
Next, you have to know the number of seconds in 10 billion years.
- (3.1536 x
) x (1.0 x
) = 3.1536 x
The last step is to multiply the number of seconds in 10 billion years to 7 million tons of mass per second.
- (3.1536 x
) x 7,000,000 = 2.20752 x
Answer:
The value of y is 8.
Step-by-step explanation:
In order to find the value of y, you have to put in x = 0 into the equation :
Let x = 0,