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3 years ago

Please help me with this one 10x+5y=72 15x+4y=80

Mathematics

2 answers:

Andre45 [30]3 years ago

7 0

I hope this helps you

Mariulka [41]3 years ago

6 0

Problem: Solve 10x+5y=72;15x+4y=80 Steps: I will try to solve your system of equations. 10x+5y=72;15x+4y=80 Step: Solve10x+5y=72for x: 10x+5y+−5y=72+−5y(Add -5y to both sides) 10x=−5y+72 10x 10 = −5y+72 10 (Divide both sides by 10) x= −1/2 y+36 5 Step: Substitute −1 2 y+ 36 5 forxin15x+4y=80: 15x+4y=80 15( −1 2 y+ 36 5 )+4y=80 −7 2 y+108=80(Simplify both sides of the equation) −7 2 y+108+−108=80+−108(Add -108 to both sides) −7 2 y=−28 −7 2 y −7 2 = −28 −7 2 (Divide both sides by (-7)/2) y=8 Step: Substitute8foryinx= −1 2 y+ 36 5 : x= −1 2 y+ 36 5 x= −1 2 (8)+ 36 5 x= 16 5 (Simplify both sides of the equation) Answer: x=16/5 and y=8

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Please help with 6-38 and give explanation on how you did it

MAXImum [283]

If you do 6-8 you get -2 so all you have to do is add the 3 and its negative. the answer is .............-32

4 0

2 years ago

Find exact value for cos(pi/16)

stellarik [79]

The exact value for cos(pi/16) would be :

cos (pi/16) = +/- √1+cosa/2

cos (pi/4) = sqrt2/2

Hope this helps

6 0

3 years ago

If Peter withdrew $47.27 from the bank and deposited $598, how would his bank account change? (Indicate how much his account wou

fredd [130]

Answer:

Since we do not know the balance we should start with, a general answer:

$b_{new} = b_{old} + \sum_{i} d_{i} - \sum_{j} w_{j} \\$

598 - 47,27 = 550,73, assuming b_old was 0$ for your example

Step-by-step explanation:

b stands for balance (old - before any deposits or withdrawals, new after all done)

d for deposits

w for withdrawals

5 0

2 years ago

Can someone please help with #16

ollegr [7]

Answer:

∠ WZX = 50°

XW is not an altitude.

Step-by-step explanation:

16. See the attached figure.

XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ

Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13

Hence, ∠ YXZ = 2 ∠ WXY

⇒ 8x + 34 = 2(10x - 13)

⇒ 8x + 34 = 20x - 26

⇒ 12x = 60

⇒ x = 5.

Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)

Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°

Hence, from Δ WXZ,

∠ WZX + ∠ WXZ + ∠ XWZ = 180°

⇒ 50° + 37° + ∠ XWZ = 180°

⇒ ∠ XWZ = 93° ≠ 90°

Hence, XW is not an altitude. (Answer)

6 0

3 years ago

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

2 years ago