Question

Solving radical equationscheck for extraneous solutions0%20%3D%20x%20%2B%203" id="TexFormula1" title=" \sqrt{2x + 30} = x + 3" alt=" \sqrt{2x + 30} = x + 3" align="absmiddle" class="latex-formula">

Answer 1

$\bf \sqrt{2x+30}=x+3\impliedby \textit{we'll squares both sides} \\\\\\ (\sqrt{2x+30})^2=(x+3)^2\implies 2x+30=x^2+6x+9 \\\\\\ 0=x^2+4x-21\implies 0=(x+7)(x-3)\implies x= \begin{cases} -7\\ 3 \end{cases}$

I don't see  an extraneous value there, -7 checks out well if you plug it in the original equation, and so does 3.

Answer 2

I don’t know this question