Evaluate the following expression using the values given: Find -a^2-3b^3+c^2+2b^3-c^2 if a=3, b=2, and c=-3.

I will report you if the answer is not correct. Make sure you include an explanation

julsineya [31]

Answer:

Step-by-step explanation:

Wow, pretty harsh. Report someone who makes a fair effort but makes a mistake. Better report yourself then, because you obviously cannot do it yourself or you wouldn't be asking.

Coordinates of the vertex seem to be (-2, 2)

It's the point where the slope of the curve is zero.

Cannot tell for certain unless we have the equation of the curve.

8 0

3 years ago

The sum of the first n terms of an arithmetic series is n/2(3n-5). If the second and fourth terms of the arithmetic series are t

sergiy2304 [10]

Let a be the first term in the arithmetic sequence. Since it's arithmetic, consecutive terms in the sequence differ by a constant d, so the sequence is

a, a + d, a + 2d, a + 3d, …

with the n-th term, a + (n - 1)d.

The sum of the first n terms of this sequence is given:

$a + (a+d) + (a+2d) + \cdots + (a+(n-1)d) = \dfrac{n(3n-5)}2$

We can simplify the left side as

$\displaystyle \sum_{i=1}^n (a+(i-1)d) = (a-d)\sum_{i=1}^n1 + d\sum_{i=1}^ni = an+\dfrac{dn(n-1)}2$

so that

$an+\dfrac{dn(n-1)}2 = \dfrac{n(3n-5)}2$

or

$a+\dfrac{d(n-1)}2 = \dfrac{3n-5}2$

Let b be the first term in the geometric sequence. Consecutive terms in this sequence are scaled by a fixed factor r, so the sequence is

b, br, br ², br ³, …

with n-th term br ⁿ⁻¹.

The second arithmetic term is equal to the second geometric term, and the fourth arithmetic term is equal to the third geometric term, so

$\begin{cases}a+d = br \\\\ a+3d = br^2\end{cases}$

and it follows that

$\dfrac{br^2}{br} = r = \dfrac{a+3d}{a+d}$

From the earlier result, we then have

$n=7 \implies a+\dfrac{d(7-1)}2 = a+3d = \dfrac{3\cdot7-5}2 = 8$

and

$n=2 \implies a+\dfrac{d(2-1)}2 = a+d = \dfrac{3\cdot2-5}2 = \dfrac12$

so that

$r = \dfrac8{\frac12} = 16$

and since the second arithmetic and geometric terms are both 1/2, this means that

$br=16b=\dfrac12 \implies b = \dfrac1{32}$

The sum of the first 11 terms of the geometric sequence is

S = b + br + br ² + … + br ¹⁰

Multiply both sides by r :

rS = br + br ² + br ³ + … + br ¹¹

Subtract this from S, then solve for S :

S - rS = b - br ¹¹

(1 - r ) S = b (1 - r ¹¹)

S = b (1 - r ¹¹) / (1 - r )

Plug in b = 1/32 and r = 1/2 to get the sum :

$S = \dfrac1{32}\cdot\dfrac{1-\dfrac1{2^{11}}}{1-\dfrac12} = \boxed{\dfrac{2047}{32768}}$

6 0

3 years ago

What is 2.8294 to the 9th power

Alina [70]

Answer: 11621.1509596

Hope this helps:) Mark me the brainliest:)

3 0

4 years ago

Any help someone.... (solve triangles using the law of sines)

gogolik [260]

Answer:

$B=51$ °

Step-by-step explanation:

Use the Law of Sines as follows:

$\frac{sinC}{c} =\frac{sinB}{b}$

Insert the appropriate values:

$\frac{sin100}{14} =\frac{sinB}{11}$

Isolate B. Multiply both sides by 11:

$11*(\frac{sin100}{14} )=11*(\frac{sinB}{11})\\\\\frac{11*sin100}{14} =sinB\\\\sinB=\frac{11*sin100}{14}$

Use the inverse:

$B=sin^{-1}(\frac{11*sin100}{14})$

Insert the equation into a calculator and round to the nearest degree:

$B=50.7\\\\B=51$

Angle B is 51°.

:Done

7 0

4 years ago

Pls help question on the photo 50 points

Katarina [22]

Answer:

10

Step-by-step explanation:

Each box is worth 2 units, because the x and y axis are counting by 2s

4 0

3 years ago

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