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bija089 [108]
3 years ago
10

Can someone help me?

Mathematics
1 answer:
IrinaVladis [17]3 years ago
3 0

Answer:

D.

Step-by-step explanation:

I think, don't trust me.

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Please write the slope-intercept form for this: A line goes through the points (5,18) and (-3,-14)
balandron [24]

y = 4x - 2

The equation of a line in ' slope- intercept form ' is

y = mx + c → (m is the slope and c the y- intercept )

To calculate m use the ' gradient formula '

m = (y₂ - y₁ )/(x₂ - x₁ )

let ( x₁, y₁ ) = (5, 18) and (x₂, y₂ ) = ( - 3, - 14 )

m = \frac{(- 14 - 18)}{( - 3 - 5)} = \frac{- 32}{- 8} = 4

the partial equation is y = 4x + c

to find c substitute either of the 2 given points into the partial equation

using (5 , 18) then 18 = 20 + c ⇒ c = 18 - 20 = - 2

y = 4x - 2 is the equation in slope- intercept form


6 0
3 years ago
.<br> Write the expression in exponential form, and then evaluate<br> 0.75x 0.75x 0.75<br> =
Dimas [21]

Answer:

3

.75

the solved version would be .421875

the numbers on top are translated in English to .75 to the power of 3.

Step-by-step explanation:

I'm pretty sure this is correct

4 0
3 years ago
Check out attachment:) I don't understand how do you find out the length ?? pls help with explanation thx
hjlf

Answer:

x=3.89

Step-by-step explanation:

I'll go in depth for you.

Before we figure out what we do, let understand what we know about this triangle.

  • We know that both triangles have a angle that measure 27°.
  • We also know EH=5
  • FG=9
  • ZG=7
  • We need to know how to find EZ

Notice how line EG and HF intersect at Angle Z. We know that if two lines intersect at an angle, it form angles called vertical angles. This means that the two angles that are vertical to each other are congruent.

This means that angle Z in both triangles both measure the same.

Now since both triangles have 2 congruent corresponding angles, we can say that the <em>Triangles</em><em> </em><em>are</em><em> </em><em>Similar</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>Angle-Angle</em><em> </em><em>Postulate</em><em>.</em>

<em>"</em><em>If</em><em> </em><em>two</em><em> </em><em> </em><em>corresponding</em><em> </em><em>angles</em><em> </em><em>of</em><em> </em><em>two</em><em> </em><em>triangles</em><em> </em><em>are</em><em> </em><em>congruent</em><em>,</em><em> </em><em>then</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>triangles</em><em> </em><em>are</em><em> </em><em>similar</em><em>.</em><em>"</em>

<em>What</em><em> </em><em>is</em><em> </em><em>mean</em><em> </em><em>when</em><em> </em><em>Triangles</em><em> </em><em>are</em><em> </em><em>similar</em><em>?</em><em> </em>

<em>It</em><em> </em><em>means</em><em> </em><em>that</em><em> </em><em>the</em><em> </em><em>similar</em><em> </em><em>triangles</em><em> </em><em>corresponding</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>equal</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>their</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>proportion</em><em>.</em>

<em>The</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em>

<em>EH</em><em> </em><em>and</em><em> </em><em>GF</em>

<em>EZ</em><em> </em><em>and</em><em> </em><em>ZG</em>

<em>HZ</em><em> </em><em>and</em><em> </em><em>HF</em><em>.</em>

<em>Our</em><em> </em><em>proportion</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>similar</em><em> </em><em>triangle</em><em>s</em><em> </em><em>is</em><em> </em>

<em>Any</em><em> </em><em>two</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>triangle</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>each</em><em> </em><em>other</em><em> </em><em>must</em><em> </em><em>equal</em><em> </em><em>the</em><em> </em><em>two</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>second</em><em> </em><em>triangles</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>each</em><em> </em><em>other</em><em> </em><em>respectively</em><em>.</em>

<em>We</em><em> </em><em>know</em><em> </em><em>FG</em><em> </em><em>and</em><em> </em><em>ZG</em><em> </em><em>so</em><em> </em><em>let</em><em> </em><em>set</em><em> </em><em>up</em><em> </em><em>our</em><em> </em><em>first</em><em> </em><em>fraction</em>

<em>\frac{fg}{zg}</em>

<em>The</em><em> </em><em>corresponding</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>both</em><em> </em><em>are</em><em> </em>

  • <em>EH</em><em> </em><em>and</em><em> </em><em>EZ</em><em> </em><em>respectively</em><em> </em><em> </em><em>so</em><em> </em><em>our</em><em> </em><em>proportion</em><em> </em><em> </em><em>looks</em><em> </em><em>like</em>
  • <em>\frac{fg}{zg}  =  \frac{eh}{ez}</em>
  • <em>Plug</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>for</em><em> </em><em>each</em><em>.</em><em> </em><em>Let</em><em> </em><em>x</em><em> </em><em>represent</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>EZ</em>
  • <em>\frac{9}{7}  =  \frac{5}{x}</em>
  • <em>Cross</em><em> </em><em>Multiply</em>
  • <em>9x = 35</em>
  • <em>x = 3 \frac{8}{9}  = 3.89</em>
  • <em>So</em><em> </em><em>x</em><em>=</em><em>3</em><em>.</em><em>8</em><em>9</em>
3 0
3 years ago
Find f(-2) for f(x)=3×2x​
Ronch [10]

substitute every x in the equation with (-2)

f(-2)=3*2*(-2) = -12

dunno if I get your equation correctly, pls check how you have written it

7 0
3 years ago
Which equation is the inverse of y = 100 - x??
denis-greek [22]

For this case we must find the inverse of the following function:

y = 100-x

To do this, we follow the steps below:

We exchange the variables:

x = 100-y

We clear the variable "x" (the variable is already cleared):

x = 100-y

We change "x" to "y":

y = 100-x

We change y for f^{-1}(x):

f^{-1} (x) = 100-x

ANswer:

f^{-1} (x) = 100-x

4 0
3 years ago
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